Question

我正试图从我60首歌曲的专辑中删除“（歌词_抒情视频）”。

import os

toBeRemoved="(Lyrics _ Lyric Video) "
path=r'E:\Users\Dylan\Desktop\MediaHuman2'
directory = os.listdir(os.fsencode(path))

for file in directory:
    filename = os.fsdecode(file)
    if toBeRemoved in filename:
        newname=filename.replace(toBeRemoved, "")
        os.rename(path+filename, path+newname)
    else:
        continue

但我一直得到这个：

    Traceback (most recent call last):
  File "E:\Users\Dylan\Desktop\filerenamer.py", line 11, in <module>
    os.rename(path+filename, path+newname)
FileNotFoundError: [WinError 2] The system cannot find the file specified: 'E:\\Users\\Dylan\\Desktop\\MediaHuman202 - NOTD - Summer of Love (Lyrics _ Lyric Video) Ft. Dagny.mp3' -> 'E:\\Users\\Dylan\\Desktop\\MediaHuman202 - NOTD - Summer of Love Ft. Dagny.mp3'

编辑：文件确实存在

Answer 1

使用os.path.join(path, filename)以使用正确分隔符的方式连接文件名。

for file in directory:
    filename = os.fsdecode(file)
    if toBeRemoved in filename:
        newname=filename.replace(toBeRemoved, "")
        os.rename(os.path.join(path, filename), os.path.join(path, newname))

Answer 2

尝试

path=r'E:\Users\Dylan\Desktop\MediaHuman2''\\'

而不是

path=r'E:\Users\Dylan\Desktop\MediaHuman2'

Answer 3

试试这段代码。它不是最好的解决方案，但它会起作用。如果符合您的需求，请告诉我。

使用功能：

path =  r'E:\NN_Music\mask rename\testing - Copy\input'
MaskRename(path, "Lyrics")

输入：

tmp1.txt
tmp2.txt
tmp3.txt

输出：

Lyric_0.txt
Lyric_1.txt
Lyric_3.txt

代码：

import os
import shutil
import operator

def diff(first, second):
        second = set(second)
        return [item for item in first if item not in second]

def MaskRename(target_path, mask):
    namesOfFiles = os.listdir(target_path)
    i = 1
    l = list()
    #removing extension
    for item in namesOfFiles:
        l.append(os.path.splitext(item)[0])

    futureNamesOfFiles = list()
    #applying new mask 
    for q in range(0, len(l),1):
        futureNamesOfFiles.append(mask + "_" + str(q))  

    listOfDiff = diff(l, futureNamesOfFiles)

    fileAfterRename = [ x for x in namesOfFiles if x.startswith(tuple(listOfDiff)) ]

    iterator = 0
    shift = 1
    for newItem in fileAfterRename:
        filename, file_extension = os.path.splitext(newItem)
        old_file = os.path.join(target_path, newItem)
        new_file = os.path.join(target_path, futureNamesOfFiles[iterator] + file_extension)
        try:
            os.rename(old_file, new_file)
            iterator = iterator + 1
        except Exception:
            new_file = os.path.join(target_path, futureNamesOfFiles[iterator + 1] + file_extension)
            os.rename(old_file, new_file)
            iterator = iterator + 2
            pass

Python文件重命名脚本

3 个答案: