Question

考虑这个Ansible任务：

- name: Set some kernel parameters
  lineinfile:
    dest: "/home/cloud-user/{{item}}.hostsubnet.json"
    regexp: '^(.*hostIP\".*)\"10.*\"(.*)$'
    line: \1"{{hostvars['{{item}}']['ansible_eth0']['ipv4']['address']}}"\2
    backrefs: yes
  with_items: "{{ groups.nodes }}"

我正在尝试遍历组[nodes]中的所有主机。对于每个节点，我想从事实中获取IP，并使用该IP 作为lineinfile regexp的替代字符串。

但这不起作用。看起来嵌套变量是不可能的。是否可以解析嵌套变量？

我使用代码收到此错误：

fatal: [master-0.ocp-36-2.teco.dev.a.tecdomain.net]: FAILED! => {
    "failed": true
}

MSG:

the field 'args' has an invalid value, which appears to include a 
variable that is undefined. The error was: 
'ansible.vars.hostvars.HostVars object' has no attribute '{{item}}'

The error appears to have been in 
'/var/lib/ansible/playbooks/hostsubnet.yml': line 27, column 7, but may
be elsewhere in the file depending on the exact syntax problem.

The offending line appears to be:


    - name: Set some kernel parameters
      ^ here

Answer 1

您正尝试使用字符串hostvars引用{{item}}中的密钥。

您应该使用变量名item代替：

line: \1"{{hostvars[item]['ansible_eth0']['ipv4']['address']}}"\2

您似乎也会对术语感到困惑：您尝试在Jinja2表达式中引用变量值（即{{ }}中包含的内容）。这个问题的答案是：使用变量名称，简单。

如何解决变量内的变量？

1 个答案: