Question

我创建了一个表格，其中只创建了一个<tr>和11 <td>。前9个<td>的值来自一个while循环，最后2个<td>值来自第二个while循环。

While循环正在<tr>中执行。现在，我得到了正确的值，但它重复了<td>作为记录的总数，例如我总共有5条记录，它给了我25条记录，第一条记录连续执行了5次并且像那样休息。

我的问题是执行一次记录，而不是重复记录。

这是我的代码：

<table id="myTable" class="table table-bordered table-hover">
    <thead>
        <tr>
            <th>First Name</th>
            <th>Last Name</th>
            <th>Email</th>
            <th>Status</th>
            <th>Reg on</th>
            <th>Upload</th>
            <th>Total Upload</th>
            <th>Sale</th>
            <th>Total Sale</th>
            <th>Purchase</th>
            <th>Total Purchase</th>     
        </tr>
    </thead>
    <tbody>         
    <?php
    include("connection.php");

    $query ="SELECT s.*, s.student_id, s.student_email, u.student_email, b.payer_email,
        COUNT(u.student_email) AS 'uploadCount',
        SUM(u.price) AS 'uploadTotal',

        COUNT(b.payer_email) AS 'buyCount',
        SUM(b.payment_amount) AS 'buyTotal'

        FROM students s

        LEFT JOIN academic_work u ON u.student_email = s.student_email
        LEFT JOIN orders b ON b.payer_email = s.student_email

        GROUP BY s.student_id
        ORDER BY s.student_id DESC
    ";

    $run = mysqli_query($con, $query) or die(mysqli_error($con));
    ?>
    <tr>    
    <?php
    while ($row=mysqli_fetch_array($run)) {
        $student_id=$row['0'];
        $student_first_name=$row[1];
        $student_last_name=$row[2];
        $student_email=$row[3];
        $student_password=$row[4];
        $student_status=$row[5];
        $student_time=$row[6];
        $uploadCount = $row['uploadCount'];
        $buyCount = $row['buyCount'];
        $uploadTotal = $row['uploadTotal'];
        $buyTotal = $row['buyTotal'];   

        $query1 ="SELECT ss.*, ss.student_id, ss.student_email, p.email,
            COUNT(p.email) AS 'purchaseCount',
            SUM(p.payment_amount) AS 'purchaseTotal'

            FROM students ss

            LEFT JOIN orders p ON p.email = ss.student_email

            GROUP BY ss.student_id
        ";

        $run1 = mysqli_query($con, $query1) or die(mysqli_error($con));

        while ($row1=mysqli_fetch_array($run1)) {
            $purchaseCount = $row1['purchaseCount'];
            $purchaseTotal = $row1['purchaseTotal'];
            ?>
                <td><?php echo $student_first_name; ?></td>
                <td><?php echo $student_last_name; ?></td>
                <td><a href="academic_work_add.php?add_academic_work=<?php echo $student_id; ?>" style="text-decoration:none;"><?php echo $student_email; ?></a></td>
                <td><?php echo $student_status; ?></td>
                <td><?php echo $student_time; ?></td>
                <td><?php if($uploadCount == 0) { echo 0; } else { echo $uploadCount; }?></td>
                <td><?php if($uploadTotal == 0) { echo 0; } else { echo $uploadTotal; }?></td>
                <td><?php if($buyCount == 0) { echo 0; } else { echo $buyCount; }?></td>
                <td><?php if($buyTotal == 0) { echo 0; } else { echo $buyTotal; }?></td>

                <td><?php if($purchaseCount == 0) { echo 0; } else { echo $purchaseCount; }?></td>
                <td><?php if($purchaseTotal == 0) { echo 0; } else { echo $purchaseTotal; }?></td>
            </tr>
        <?php
        }
    }
    ?>
    </tbody>
</table>

提前致谢！

Answer 1

您的$query1在每次迭代时循环遍历表的所有行。使用where子句然后它将返回您想要的1行。使用$row的ID定位正确的行。您应该对此进行参数化，这样您就不会打开SQL注入（https://security.stackexchange.com/questions/146595/second-order-sql-injection-protection）。

这也可以在1个查询中完成，循环查询通常是不正确的实现。

列在php中的多个while循环内重复（ID的总数）时间

1 个答案: