Question

The content of my reduced CSV test file is the following.

arr = ["company,location,region,service,price,duration,disabled\n",
       "Google,Berlin,EU,Design with HTML/CSS,120,30,FALSE\n",
       "Google,San Francisco,US,Design with HTML/CSS,120,30,FALSE\n",
       "Google,San Francisco,US,Restful API design,1500,120,FALSE\n",
       "Apple,London,EU,Design with HTML/CSS,120,30,FALSE\n",
       "Google,Berlin,EU,Design with HTML/CSS,120,30,FALSE\n",
       "Apple,Berlin,EU,Restful API design,1500,120,FALSE\n",
       "IBM,San Francisco,US,Design with HTML/CSS,120,30,TRUE\n",
       "Google,San Francisco,US,Design with HTML/CSS,120,30,FALSE\n",
       "IBM,Berlin,EU,Restful API design,1500,120,TRUE\n",
       "IBM,London,EU,Restful API design,1500,120,TRUE\n",
       "IBM,Berlin,EU,Restful API design,1500,120,TRUE\n",
       "IBM,London,EU,Restful API design,1500,120,TRUE\n",
       "IBM,San Francisco,US,Design with HTML/CSS,120,30,TRUE\n",
       "Google,Berlin,EU,Advanced AngularJS,1200,180,FALSE\n",
       "Google,Berlin,EU,Restful API design,1500,120,FALSE\n", 
       "Google,London,EU,Restful API design,1500,120,FALSE\n",
       "Apple,San Francisco,US,Design with HTML/CSS,120,30,FALSE\n",
       "Google,San Francisco,US,Restful API design,1500,120,FALSE\n",
       "IBM,Berlin,EU,Restful API design,1500,120,TRUE\n"]

这里argc是一个整数变量，表示传递的参数数量。 argv是一个指向字符的指针数组我怀疑是否看到了使用

的程序

main(int argc,char *argv[])
{
......;
......;
}

它是否有效我们可以使用argv作为指向整数的指针数组吗？

Answer 1

#include <stdio.h>

int main(int argc, int*argv[])
{
int a=3;
int b=4;

printf("\n%s", (char*)argv[1]);
return 0;
}

命令行参数：abcd

输出：abcd

我已经编译了上面的代码并且在我尝试的编译器中完美地工作了。 似乎某些编译器允许使用int* argv[]。我认为这是编译器特定的一些将允许它而其他不会。你必须为传递的参数提供适当的转换。

注意：我并不是说它适用于每个编译器和每个环境。：）

我们可以在命令行参数中使用整数指针

1 个答案: