Question

我正在使用此代码对字典进行排序：

var sortedArray = dict.sorted(by: {$0.0 < $1.0})

它正在排序，但不是我希望它在下面看到的方式：

["1", "10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "2", "20", "21", "22", "23", "24", "3", "4", "5", "6", "7", "8", "9"]

的内容

 ["1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11"]

完整的词典：

["17": 00:00:89, "12": 00:00:89, "20": 00:00:89, "23": 00:00:89, "19": 00:00:89, "22": 00:00:89, "13": 00:00:89, "9": 00:00:00, "8": 00:00:00, "6": 00:00:89, "7": 00:17:13, "name": G. Snyder, "24": 00:00:89, "14": 00:00:89, "16": 00:00:89, "18": 00:00:89, "15": 00:00:89, "2": 00:02:02, "11": 00:00:89, "1": 00:01:01, "3": 00:01:59, "4": 00:03:12, "21": 00:00:89, "10": 00:00:33, "5": 00:06:15]

编辑:(仍然没有工作）

var sortedArray = dict.sorted(by: {$0.0 < $1.0})
sortedArray.removeLast()
sortedArray = dict.sorted(by: {Int($0.0)! < Int($1.0)!})

Answer 1

您可以使用通用实例方法localizedStandardCompare

对字典键进行排序

只要文件名或其他字符串是，就应该使用此方法在类似Finder的排序的列表和表格中显示适当。这种方法的确切排序行为是不同的在不同的语言环境下，可能会在将来的版本中更改。这个 method使用当前的语言环境。

let dict = ["17": "00:00:89", "12": "00:00:89", "20": "00:00:89", "23": "00:00:89", "19": "00:00:89", "22": "00:00:89", "13": "00:00:89", "9": "00:00:00", "8": "00:00:00", "6": "00:00:89", "7": "00:17:13", "name": "G. Snyder", "24": "00:00:89", "14": "00:00:89", "16": "00:00:89", "18": "00:00:89", "15": "00:00:89", "2": "00:02:02", "11": "00:00:89", "1": "00:01:01", "3": "00:01:59", "4": "00:03:12", "21": "00:00:89", "10": "00:00:33", "5": "00:06:15"]

let sortedTuples = dict.sorted{$0.key.localizedStandardCompare($1.key) == .orderedAscending}
sortedTuples  // [(key "1", value "00:01:01"), (key "2", value "00:02:02"), (key "3", value "00:01:59"), (key "4", value "00:03:12"), (key "5", value "00:06:15"), (key "6", value "00:00:89"), (key "7", value "00:17:13"), (key "8", value "00:00:00"), (key "9", value "00:00:00"), (key "10", value "00:00:33"), (key "11", value "00:00:89"), (key "12", value "00:00:89"), (key "13", value "00:00:89"), (key "14", value "00:00:89"), (key "15", value "00:00:89"), (key "16", value "00:00:89"), (key "17", value "00:00:89"), (key "18", value "00:00:89"), (key "19", value "00:00:89"), (key "20", value "00:00:89"), (key "21", value "00:00:89"), (key "22", value "00:00:89"), (key "23", value "00:00:89"), (key "24", value "00:00:89"), (key "name", value "G. Snyder")]

Answer 2

因为sorted(by:)如何进行比较的逻辑与给定元素的相等逻辑有关（你不能对不可比元素的数组进行排序），输出将基于如何字符串比较应该是 - 因为给定的let sorted = dict.sorted { if let key1Int = Int($0.key), let key2Int = Int($1.key) { return key1Int < key2Int } return true }键是字符串 - （＆＃34; 1＆＃34;字符小于＆＃34; 2＆＃34;）。

但是，您可能需要将键值转换为Ints然后排序：

{{1}}

此时，即使键值不可投射到Int。

，排序也应该有效

Answer 3

由于您的词典由字符串组成，因此按字母顺序排序。您可以尝试的是这样的事情：

let sortedArray = dict.sorted(by: {Int($0.0)! < Int($1.0)!})

编辑：如果不是所有的键都可以转换为数字，我们必须使它更复杂：

let sortedArray = dict.sorted(by: {
  let a = Int($0.0) ?? 0
  let b = Int($1.0) ?? 0
  return a < b
})

这会将“词典”中的“名称”置于顶部。

如何按字符串键排序字典？

3 个答案: