在swift

Question

我是一个非常新的快速并花了一整天试图解析简单的json，接受了思想的websockets。最后我解析了（有点），但很多事情仍然超出了我的理解，我要求一些解释。

好的，这是我到目前为止所得到的

首先，我声明变量QUOTES，它将是Dictionary，与json

相同

var QUOTES: Dictionary<String, Dictionary<String, Any>>

我希望我的QUOTES var在最后看起来像这样：

{
  "AAPL": {name: "Apple Comp", "price": 100},
  "F": {name: "Ford Comp", "price": 200}
}

当我的websocket接收数据时，我想用接收到的数据填充QUOTES。

socket.on("q"){data, ack in

        //data looks like this: [{q:[{c: "AAPL", price: 100}, {c: "F", price: 100}]}]


        //I convert first element of received [Any] to dictionary
        let object = data[0] as! Dictionary<String, NSArray>

        //I get array of quotes out of received data
        let quotes = object["q"] as! [Dictionary<String, Any>]

        //Now I want to iterate through received quotes to fill me QUOTES variable declared in the very beginning
        for quote in quotes {

            //I know ticker of current quote
            let ticker = quote["c"] as! String

            //Not sure if I have to do it - if QUOTES does not have current ticker in dictionary, I create it as empty dictionary

            if (QUOTES[ticker] == nil) {
                QUOTES[ticker] = [String: Any]()
            }


            //Now I iterate properties of received quote
            for(k,v) in quote {

                //And I want to fill my QUOTES dictionary,
                // but I get compile error
                //Value of optional type '[String : Any]?' not unwrapped; did you mean to use '!' or '?'? 
                //I don't understand what compiler wants me to do?
                QUOTES[ticker][k] = v
            }
        }
    }

但我收到编译错误

  

可选类型的值＆＃39; [字符串：任意]？＆＃39;没有打开;你的意思是使用＆＃39;！＆＃39;或者＆＃39;？＆＃39;？

我不明白编译器要我做什么？