如何从strtok（）获取每个令牌？

Question

我有一个带字符串的函数。我复制了一个字符串和char *token;。我说token = strtok(myString, " ");然后用while(token != NULL) {...}开始一个while循环，我在while循环中做了一些事情。在while循环结束时，我说token = strtok(NULL, " ");似乎遵循examples I've seen online。我的输入字符串是＆＃34;这是一个我会搞砸的字符串＆＃34;我的第一个标记是＆＃34;这个＆＃34;这很棒，但之后我说token = strtok(NULL, " ");令牌似乎是＆＃34;（null）＆＃34;而不是＆＃34;是＆＃34;。我想知道为什么。这是我的代码：

int numReps2(char *s) {
    printf("inside numReps2 with \"%s\"\n", s);
    // iterate through s until you find a space
    // do matchingwords with the word and an accumulator string that you build char x char
    int l = mystrlen(s);
    char *copy = malloc(1+(sizeof(char) * l));
    mystrcpy(copy, s);

    char *accu = malloc(1+(sizeof(char) * l));

    int ret = 0;
    printf("about to tokenize \"%s\"\n", copy);

    char *token;
    const char delim[2] = " ";

    token = strtok(copy, delim);
    while(token != NULL) {
        if(matchingWords(accu, copy)) {
            printf("match-> accu is \"%s\" and token is \"%s\"\n", accu, token);
            // we have a match
            ret++;
        } else {
            // no match, add to accu
            char *temp = mystrappend(token, " ");  // stick a space after it
            printf("no match, adding \"%s\" to \"%s\", token is still \"%s\"\n", temp, accu, token);
            accu = mystrappend(accu, temp);
            printf("accu is now \"%s\"\n", accu);
            free(temp);
            printf("after freeing temp, token is \"%s\"\n", token);
        }
        printf("here is what's after token: %c\n", *(token+strlen(token)+2));
        token = strtok(NULL, delim);
        printf("just tok'd again, now it's \"%s\"\n", token);
    }

    free(copy);
    free(accu);
    return ret;
}