是否有更有效的方法来执行此查询？它运行，但大约需要6分钟才能完成。我相信多个select语句会产生延迟。由他们自己运行任何返回结果＆lt; 1秒。
SELECT
x.HPCODE AS [Health Plan],
x.HPFROMDT AS [Eff Date],
x.MEMBID AS [ID #],
x.LASTNM AS [Mbr L Name],
x.FIRSTNM AS [Mbr F Name],
x.BIRTH AS DOB,
DATEDIFF(YEAR, birth, GETDATE()) AS Age,
x.PCP as [Prov ID#],
Y.LASTNAME as [Prov L Name],
Y.FIRSTNAME as [Prov F Name],
PA.PHONE as [Provider Phone],
(SELECT MAX(cd.FROMDATESVC)
FROM [dbo].[Claim_Masters] cm
LEFT JOIN [dbo].[Claim_Details] cd ON cm.claimno = cd.claimno
AND cm.MEMBID = x.MEMBID
WHERE LEFT(cd.PROCCODE, 5) IN ('G0402', 'G0438', 'G0439')
AND YEAR(cm.SERVICEDATEFROM) = YEAR(GETDATE())) AS [AWV],
(SELECT MAX(cd.FROMDATESVC)
FROM [dbo].[Claim_Masters] cm
LEFT JOIN [dbo].[Claim_Details] cd ON cm.claimno = cd.claimno
AND cm.MEMBID = x.MEMBID
WHERE (LEFT(cd.PROCCODE, 5) IN ('G0402', 'G0438', 'G0439')
OR RIGHT(cd.PROCCODE, 5) IN ('99490', '99487', '99489'))
AND YEAR(cm.SERVICEDATEFROM) = YEAR(GETDATE())) AS [CCM],
(select max(cd.FROMDATESVC) from [dbo].[Claim_Masters] cm left join [dbo].[Claim_Details] cd on cm.claimno = cd.claimno and cm.MEMBID = x.MEMBID Where (Right(cd.PROCCODE,5) in ('99495','99496') )and Year(cm.SERVICEDATEFROM) = Year(Getdate())) as [TCM],
(select max(cd.FROMDATESVC) from [dbo].[Claim_Masters] cm left join [dbo].[Claim_Details] cd on cm.claimno = cd.claimno and cm.MEMBID = x.MEMBID Where (Right(cd.PROCCODE,5) in ('99211','99212','99213','99214','99215','99201','99202','99203','99204','99205') )and Year(cm.SERVICEDATEFROM) = Year(Getdate())) as [Office],
(select max(cd.FROMDATESVC) from [dbo].[Claim_Masters] cm left join [dbo].[Claim_Details] cd on cm.claimno = cd.claimno and cm.MEMBID = x.MEMBID Where (Right(cd.PROCCODE,5) = '1170F' )and Year(cm.SERVICEDATEFROM) = Year(Getdate())) as [FUNC],
(select max(cd.FROMDATESVC) from [dbo].[Claim_Masters] cm left join [dbo].[Claim_Details] cd on cm.claimno = cd.claimno and cm.MEMBID = x.MEMBID Where (Right(cd.PROCCODE,5) in ('1157F','1158F') )and Year(cm.SERVICEDATEFROM) = Year(Getdate())) as [ACP],
(select max(cd.FROMDATESVC) from [dbo].[Claim_Masters] cm left join [dbo].[Claim_Details] cd on cm.claimno = cd.claimno and cm.MEMBID = x.MEMBID Where (Right(cd.PROCCODE,5) in ('0521F','1125F','1126F') )and Year(cm.SERVICEDATEFROM) = Year(Getdate())) as [PAIN],
(select max(cd.FROMDATESVC) from [dbo].[Claim_Masters] cm left join [dbo].[Claim_Details] cd on cm.claimno = cd.claimno and cm.MEMBID = x.MEMBID Where (Right(cd.PROCCODE,5) in ('99605','99606','1160F','1111F','1159F') )and Year(cm.SERVICEDATEFROM) = Year(Getdate())) as [MTM]
FROM
[dbo].[MEMB_COMPANY] X
LEFT JOIN
[dbo].[PROV_COMPANY] Y ON X.PCP = Y.PROVID
JOIN
[dbo].[PROV_ADDINFO] PA ON Y.PROV_MPI_NO = PA.PROV_MPI_NO
AND (PA.EDI_DEFAULT = 1)
WHERE
(ISNULL(x.OPTHRUDT, '') = '' OR
x.OPTHRUDT > GETDATE())
AND X.HPCODE = 'CHPS'
答案 0 :(得分：0)
我假设MEMB_COMPANY和PROV_COMPANY之间的关系为1：M，PROV_COMPANY和PROV_ADDINFO之间的关系为1：M。然后应该可以使用GROUP BY和conditional aggregation重写子查询。类似于以下查询。我重写了前两个子查询，我想这个想法很清楚。
SELECT
x.HPCODE as [Health Plan]
,x.HPFROMDT as [Eff Date]
,x.MEMBID AS [ID #]
,x.LASTNM as [Mbr L Name]
,x.FIRSTNM as [Mbr F Name]
,x.BIRTH as DOB
,datediff(year,birth,getdate()) as Age
,x.PCP as [Prov ID#]
,Y.LASTNAME as [Prov L Name]
,Y.FIRSTNAME as [Prov F Name]
,PA.PHONE as [Provider Phone]
,max(CASE WHEN left(cd.PROCCODE,5) in ('G0402','G0438','G0439') and Year(cm.SERVICEDATEFROM) = Year(Getdate()) THEN cd.FROMDATESVC END)
,max(CASE WHEN left(cd.PROCCODE,5) in ('G0402','G0438','G0439') or Right(cd.PROCCODE,5) in ('99490','99487','99489') and Year(cm.SERVICEDATEFROM) = Year(Getdate()) THEN cd.FROMDATESVC END)
-- the subsequent conditions follows
FROM [dbo].[MEMB_COMPANY] X
LEFT JOIN [dbo].[PROV_COMPANY] Y ON X.PCP = Y.PROVID
Join [dbo].[PROV_ADDINFO] PA ON Y.PROV_MPI_NO = PA.PROV_MPI_NO and (PA.EDI_DEFAULT = 1)
LEFT JOIN [dbo].[Claim_Masters] cm ON cm.MEMBID = x.MEMBID
LEFT JOIN [dbo].[Claim_Details] cd on cm.claimno = cd.claimno
WHERE (isnull(x.OPTHRUDT, '') = '' or x.OPTHRUDT > GETDATE()) and X.HPCODE = 'CHPS'
GROUP BY x.MEMBID, x.HPCODE ,x.HPFROMDT, x.LASTNM, x.FIRSTNM, x.BIRTH, x.PCP, Y.LASTNAME, Y.FIRSTNAME, PA.PHONE
如果您预先计算表格中的left(cd.PROCCODE,5)和right(cd.PROCCODE,5)值，我认为您的查询也可以加速。
答案 1 :(得分：0)
子查询通常很慢......您应该尝试使用以下语法来避免它们：
SELECT
x.HPCODE as [Health Plan]
,x.HPFROMDT as [Eff Date]
,x.MEMBID AS [ID #]
,x.LASTNM as [Mbr L Name]
,x.FIRSTNM as [Mbr F Name]
,x.BIRTH as DOB
,datediff(year,birth,getdate()) as Age
,x.PCP as [Prov ID#]
,Y.LASTNAME as [Prov L Name]
,Y.FIRSTNAME as [Prov F Name]
,PA.PHONE as [Provider Phone]
,MAX(CASE WHEN left(cd.PROCCODE,5) in ('G0402','G0438','G0439') THEN cd.FROMDATESVC ELSE NULL END) as [AWV]
,MAX(CASE WHEN left(cd.PROCCODE,5) in ('G0402','G0438','G0439') or Right(cd.PROCCODE,5) in ('99490','99487','99489') THEN cd.FROMDATESVC ELSE NULL END) as [CCM]
,MAX(CASE WHEN Right(cd.PROCCODE,5) in ('99495','99496') THEN cd.FROMDATESVC ELSE NULL END) as [TCM]
,MAX(CASE WHEN Right(cd.PROCCODE,5) in ('99211','99212','99213','99214','99215','99201','99202','99203','99204','99205') THEN cd.FROMDATESVC ELSE NULL END) as [Office]
,MAX(CASE WHEN Right(cd.PROCCODE,5) = '1170F' THEN cd.FROMDATESVC ELSE NULL END) as [FUNC]
,MAX(CASE WHEN Right(cd.PROCCODE,5) in ('1157F','1158F') THEN cd.FROMDATESVC ELSE NULL END) as [ACP]
,MAX(CASE WHEN Right(cd.PROCCODE,5) in ('0521F','1125F','1126F') THEN cd.FROMDATESVC ELSE NULL END) as [PAIN]
,MAX(CASE WHEN Right(cd.PROCCODE,5) in ('99605','99606','1160F','1111F','1159F') THEN cd.FROMDATESVC ELSE NULL END) as [MTM]
FROM [dbo].[MEMB_COMPANY] X
LEFT JOIN [dbo].[PROV_COMPANY] Y ON (X.PCP = Y.PROVID)
INNER JOIN [dbo].[PROV_ADDINFO] PA ON (Y.PROV_MPI_NO = PA.PROV_MPI_NO and (PA.EDI_DEFAULT = 1))
LEFT JOIN [dbo].[Claim_Masters] cm ON (cm.MEMBID = x.MEMBID
LEFT JOIN [dbo].[Claim_Details] cd ON (cm.claimno = cd.claimno)
where (isnull(x.OPTHRUDT, '') = '' or x.OPTHRUDT > GETDATE()) and X.HPCODE = 'CHPS'
GROUP BY x.HPCODE,x.HPFROMDT,x.MEMBID,x.LASTNM,x.FIRSTNM,x.BIRTH,datediff(year,birth,getdate()),x.PCP,Y.LASTNAME,Y.FIRSTNAME,PA.PHONE