Question

我以这种方式显示通知：

let notification = NSUserNotification()
notification.title = "Title lorem ipsum"
notification.informativeText = "Lorem ipsum"
notification.soundName = NSUserNotificationDefaultSoundName
notification.hasActionButton = true
notification.otherButtonTitle = "Other Button"
notification.actionButtonTitle = "Action Button"
NSUserNotificationCenter.default.deliver(notification)

处理通知点击事件：

func userNotificationCenter(_ center: NSUserNotificationCenter, didActivate notification: NSUserNotification) {
        switch (notification.activationType) {
        case .additionalActionClicked:
            print("Action:")
        case .actionButtonClicked:
            print("Action Button clicked")
            takeBreakClicked()
        case .contentsClicked:
            print("Contents clicked") 
        case .none:
            print("none")
        case .replied:
            print("reply clicked")
        }
    }

此通知将有2个按钮。问题是如何获得＆＃34;其他按钮＆＃34;点击事件？

Answer 1

我知道这是一个古老的问题，答案不是特别令人满意，但是也许可以节省一些时间：

我得出的结论是，当用户单击NSUserNotification中的“关闭”按钮时，根本没有未交付事件。（或者将“关闭”按钮重命名为使用otherButtonTitle属性的任何内容。）

如何处理NSUserNotification已关闭的事件

1 个答案: