无法将变量插入curl网址

Question

似乎无论何时我在shell上测试它都可以，但是当我从脚本运行它时它不会。

外壳：

fips=55555
echo https://www2.census.gov/geo/tiger/TIGER2016/ROADS/tl_2016_$fips'_'roads.zip
>>https://www2.census.gov/geo/tiger/TIGER2016/ROADS/tl_2016_55555_roads.zip

我正在尝试在文本文件中循环浏览一些数据：

将其解析/输入到curl url：

但是输出的字符串的开头是这样覆盖的：

./readFipsData.txt
>>_roads.zipw2.census.gov/geo/tiger/TIGER2016/ROADS/tl_2016_48001

注意：如果有任何不同，我正在使用Git Bash for Windows。

cat ./testFipsData.txt |
while read line
do
    counter=0
    for col in $line
    do
    if [ $counter == 0 ]
    then
        state=$col
    elif [ $counter == 1 ]
    then
        county=$col
    elif [ $counter == 2 ]
    then
        fips=$col
    fi
        ((counter++))
    done
#curl -k -o ./$county.zip "https://www2.census.gov/geo/tiger/TIGER2016/ROADS/tl_2016_$fips_roads.zip"
echo https://www2.census.gov/geo/tiger/TIGER2016/ROADS/tl_2016_$fips'_'roads.zip
done

Answer 1

感谢您在这里提出的所有建议：

cat ./testFipsData.txt | 
while read state county fips
do
fips=${fips%$'\r'}
curl -k -o ./$county.zip https://www2.census.gov/geo/tiger/TIGER2016/ROADS/tl_2016_$fips'_'roads.zip
done