Question

所以，我有一个由JSON Parsing创建的ListView，我希望一旦从ListView中选择一个项目添加到另一个ArrayList，我使用HashMap，因为它是一组数据。问题是，如果我选择一个它工作正常，但是一旦我选择了第二个，那么我的ArrayList将具有SECOND一次两次，如果我再次执行第三个三次，依此类推。我附上下面的代码部分，任何帮助将不胜感激。

  lv.setOnItemClickListener(new AdapterView.OnItemClickListener() {

                public void onItemClick(AdapterView<?> adapter, View v, int position, long id) {

                    Toast.makeText(getApplicationContext(),
                            "Bookmarked",
                            Toast.LENGTH_LONG)
                            .show();


//adding the data from the list view to the HashMap object

                    HashMap<String, String> obj = (HashMap<String, String>) adapter.getItemAtPosition(position);
                    String name = (String) obj.get("name");
                    String rating = (String) obj.get("rating");
                    String summary = (String) obj.get("summary");
                    String date = (String) obj.get("publ. date");
                    String type = (String) obj.get("type");
                    String suggested_link = (String) obj.get("suggested_link_text");
                    String link = (String) obj.get("link");


                    bookmarked.put("rating", rating);
                    bookmarked.put("name", name);
                    bookmarked.put("summary", summary);
                    bookmarked.put("publ. date", date);
                    bookmarked.put("type", type);
                    bookmarked.put("suggested_link_text", suggested_link);
                    bookmarked.put("link", link);


//the ArrayList that contains the HashMap data
                    selected.add(bookmarked);

                    Log.v("Selected: ", selected.toString());

                }});

Answer 1

这是因为您在每次点击时都会覆盖bookmarked对象，并且您每次都会将同一个对象添加到列表中。解决方案是每次都创建一个新的bookmarked对象：

HashMap<String, String> bookmarked = new HashMap<String, String>();
bookmarked.put("rating", rating);
                bookmarked.put("name", name);
                bookmarked.put("summary", summary);
                bookmarked.put("publ. date", date);
                bookmarked.put("type", type);
                bookmarked.put("suggested_link_text", suggested_link);
                bookmarked.put("link", link);

从ListView创建的ArrayList与HashMap重复而不是添加

1 个答案: