发送到服务器时添加一些字符的Base64字符串

时间：2017-09-29 11:24:58

标签： php ios

我正在处理一个应用程序，我正在向服务器发送base64编码的图像字符串。字符串是正确的，当我从XCode调试器窗口复制字符串并从PHP生成图像时，它会生成一个正确的有效图像。但是当我通过webservice发送相同的字符串时，它会在字符串中添加一些额外的字符，并且图像会被破坏。

如何从此字符串中删除这些额外字符。

以下是来自XCode调试器的图像的base64字符串：

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AAEAAIdpAAQAAAABAAAAJgAAAAAAA6ABAAMAAAABAAEAAKACAAQAAAABAAABd6AD
AAQAAAABAAABHgAAAAD/7QA4UGhvdG9zaG9wIDMuMAA4QklNBAQAAAAAAAA4QklN
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这是从服务器回显的字符串：

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1 个答案:

答案 0 :(得分：1)

如评论中所述，每插入64个字符“rn”。此外，“+”替换为“”。让我们改变一下。
使用输出字符串定义$s：

$chars = str_split($s);
for($i = 64; $i < strlen($s); $i+=66) {
    unset($chars[$i]);
    unset($chars[$i+1]);
}
$new_s = str_replace(" ", "+", implode($chars));

for($i = 0; $i < strlen($new_s); $i++){
    if($i > 0 && $i % 64 == 0)
        echo "<br />";
    echo $new_s[$i];
}

演示：http://sandbox.onlinephpfunctions.com/code/33ef917c4403560c469d8e9eea2ae88b4c6b732e
差异：https://www.diffchecker.com/ajAv578C

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