Question

交易表

No   Date        Amount 
1   06-07-2017   1000
2   06-07-2017   1500
3   08-07-2017   2000
4   09-07-2017   2000
5   09-07-2017   2000
6   09-07-2017   2000

是否可以通过单个查询（无查询循环）实现此结果

No   Date        Total Amount
1   06-07-2017      2500
2   08-07-2017      2000
3   09-07-2017      6000

Answer 1

您在寻找Group By吗？

    select Trunc("Date"), -- we have to put ".." since Date is a Keyword in Oracle
           sum(Amount) as "Total Amount"
      from MyTable
  group by Trunc("Date")
  order by Trunc("Date")

修改：似乎Date字段包含日期和时间，而时间部分应该截断< / em> - Trunc - 汇总时（参见评论）

Answer 2

确切结果：

select row_number() over (order by date) as No,
       date, sum(amount) as "Total Amount"
from t
group by date
order by date;

注意：在Oracle中，date数据类型可以包含时间组件 - 这可能在输出中不可见。如果是这样，聚合不会按预期执行。如果是这种情况，那么：

select row_number() over (order by trunc(date)) as No,
       trunc(date) as date, sum(amount) as "Total Amount"
from t
group by trunc(date)
order by trunc(date);

选择按日期区分SQL Oracle

2 个答案: