我有一个数据库表:
select SiteName, LastName, Id, Type, StartDate, StartTime, Duration, RN
来自mytable
SiteName LastName Id Type StartDate StartTime Duration RN
-------- -------- -- ---- --------- --------- -------- --
PK Jones 284 iov 20171026 830 5 1
PK Jones 284 iov 20171026 845 5 2
PK Jones 284 iov 20171113 740 5 1
PK Jones 284 iov 20171113 845 5 2
PK Jones 284 iov 20171114 855 5 1
PK Jones 284 iov 20171201 640 5 1
PK Jones 284 iov 20171201 845 5 2
PK Jones 284 iov 20171206 840 5 1
PK Jones 284 iov 20171206 845 5 2
PK Jones 284 iov 20171208 855 5 1
PK Jones 284 iov 20171214 840 5 1
PK Jones 284 iov 20171214 845 5 2
PK Jones 284 iov 20171215 840 5 1
PK Jones 284 iov 20171215 845 5 2
PK Jones 284 iov 20171222 840 5 1
我的查询给了我这些结果:
select SiteName, LastName, Id, Type, StartDate, min(StartTime), Duration
from mytable
where RN = 2
group by SiteName, LastName, Id, Type, StartDate, Duration
SiteName LastName Id Type StartDate StartTime Duration
-------- -------- -- ---- --------- --------- --------
PK Jones 284 iov 20171026 845 5
PK Jones 284 iov 20171113 845 5
PK Jones 284 iov 20171201 845 5
PK Jones 284 iov 20171206 845 5
PK Jones 284 iov 20171214 845 5
PK Jones 284 iov 20171215 845 5
PK Jones 284 iov 20171222 845 5
当RN = 2时,我想返回SiteName,LastName,Id,Type,StartDate,min(StartTime),每个StartDate组的持续时间。 例如,我的结果应如下所示:
SiteName LastName Id Type StartDate StartTime Duration
-------- -------- -- ---- --------- --------- --------
PK Jones 284 iov 20171026 830 5
PK Jones 284 iov 20171113 740 5
PK Jones 284 iov 20171201 640 5
PK Jones 284 iov 20171206 840 5
PK Jones 284 iov 20171214 840 5
PK Jones 284 iov 20171215 840 5
PK Jones 284 iov 20171222 840 5
答案 0 :(得分:0)
您可以尝试以下SQL查询。
SELECT SiteName,
LastName,
Id,
Type,
StartDate,
MIN(StartTime) StartTime,
Duration
FROM mytable
WHERE StartDate IN (SELECT StartDate
FROM mytable
WHERE RN = 2)
GROUP BY SiteName,
LastName,
Id,
Type,
StartDate,
Duration
SiteName LastName Id Type StartDate StartTime Duration
PK Jones 284 iov 2017-10-26 830 5
PK Jones 284 iov 2017-11-13 740 5
PK Jones 284 iov 2017-12-01 640 5
PK Jones 284 iov 2017-12-06 840 5
PK Jones 284 iov 2017-12-14 840 5
PK Jones 284 iov 2017-12-15 840 5