Question

我有这张桌子：

ID  | Status   | Date  
----+----------+--------------
1   |    1     |   01-01-2017    
2   |    1     |   26-04-2016   
2   |    4     |   20-10-2016  
3   |    1     |   05-11-2015  
3   |    2     |   20-03-2016  
4   |    4     |   06-06-2015  
5   |    1     |   10-04-2017  
5   |    3     |   21-12-2016  
5   |    2     |   25-02-2013  
5   |    4     |   11-03-2014

我想要的结果是：

ID  |  Status1 |  Status2 | Status3  |  Status4 |  Date  
----+----------+----------+----------+----------+------------
1   |    1     |          |          |          |  01 01 2017  
2   |    1     |          |          |          |  26 04 2016   
2   |          |          |          |    4     |  20 10 2016  
3   |    1     |          |          |          |  05 11 2015  
3   |          |    2     |          |          |  20 03 2016  
4   |          |          |          |    4     |  06 06 2015  
5   |    1     |          |          |          |  10 04 2017  
5   |          |          |    3     |          |  21 12 2016  
5   |          |    2     |          |          |  25 02 2013  
5   |          |          |          |    4     |  11 03 2014

我该如何进行查询？

Answer 1

您可以使用CASE语句来实现此目的。请注意我将日期重命名为sdate，因为日期为reserved word。

CREATE TABLE myTable (id INT, status INT, [sdate] date)

INSERT INTO myTable VALUES (1, 1, '01-01-2017')
                           ,(2, 1, '04-26-2017')
                           ,(2, 4, '10-20-2016')


    SELECT id
           ,CASE WHEN status = 1 then status else NULL end as status1
           ,CASE WHEN status = 2 then status else NULL end as status2
           ,CASE WHEN status = 3 then status else NULL end as status3
           ,CASE WHEN status = 4 then status else NULL end as status4
           ,sdate
    FROM myTable

SQl Server - 具有不同值的2个相等列

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