Question

目前我正在为使用mysql的用户写一个数据库，用户有几个字段，我希望他们能够使用表单更新他们当前的用户配置文件。在占位符中，我想显示他们当前的信息。提交应更改提供的信息并更新表格。

<h2>Update your profile</h2>
<div class="form">
    <form action="/updateprofile">
        <input type="text" name="Email_Address" placeholder="Email Address">
        <input type="text" name="First_Name" placeholder="First Name">
        <input type="text" name="Last_Name" placeholder="Last Name">
        <input class="button" type="submit">
    </form>
</div>

这是servlet代码{并非全部只写入sqldb}

protected void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException {

    //Obtain submitted form data
    String firstName = req.getParameter("First_Name");
    String lastName = req.getParameter("Last_Name");
    String username = req.getParameter("User_Name");
    String email = req.getParameter("Email_Address");
    String password =req.getParameter("Password");

    try {
    //Setup the Database datasource
    Context    ctx = new InitialContext();
    Context env = ( Context )ctx.lookup( "java:comp/env" );
    DataSource ds = ( DataSource )env.lookup( "jdbc/carRentalSystem");
    Connection conn = ds.getConnection();

    //Prepare the SQL statmenet to insert the values
    PreparedStatement stmt = conn.prepareStatement("INSERT INTO userdetails(First_Name, Last_Name, Email_Address, Password, User_Name)  VALUES (?,?,?,?,?)");
    stmt.setString(1, firstName);
    stmt.setString(2, lastName);
    stmt.setString(3, email);
    stmt.setString(4, password);
    stmt.setString(5, username);

    //Execute the insert
    stmt.executeUpdate();
    conn.close();

    //Dispatch into success page
    RequestDispatcher requestDispatcher = req.getRequestDispatcher("login.html");
    requestDispatcher.forward(req, res);
}
    catch(Exception e){
        System.out.println(e);
    }

Answer 1

我把它更改为更新而不是插入，这是一个很大的愚蠢的错误，我道歉花了很长时间。

如何使用servlet更新用户信息mysql

1 个答案: