Question

我有两个长度不等的对象，我想根据'mac_id'进行合并。我正在使用lodash _.merge()，但它与变量对象长度不兼容。

obj4=[ 
  { mac_id: '00-17-0d-00-00-30-47-fa',
    sent_mail_time: '2017-09-28 11:07:0' },
  { mac_id: '00-17-0d-00-00-30-48-18',
    sent_mail_time: '2017-09-28 11:07' }
    ];

obj3=[ 
  { mac_id: '00-17-0d-00-00-30-4d-94',
    notif_time: '2017-09-28 10:16:28' },
  { mac_id: '00-17-0d-00-00-30-47-fa',
    notif_time: '2017-09-28 10:14:28' },
  { mac_id: '00-17-0d-00-00-30-49-58',
    notif_time: '2017-09-28 10:26:28' } ]

使用_.groupBy('mac_id')我获得了所需的数据，但没有采用结构化的方式。

我需要遵循哪些方法才能使最终结果像这样？

[ 
      { mac_id: '00-17-0d-00-00-30-4d-94',
        notif_time: '2017-09-28 10:16:28' },
      { mac_id: '00-17-0d-00-00-30-47-fa',
        sent_mail_time: '2017-09-28 11:07:0',
        notif_time: '2017-09-28 10:14:28' },
      { mac_id: '00-17-0d-00-00-30-49-58',
        notif_time: '2017-09-28 10:26:28' },
        { mac_id: '00-17-0d-00-00-30-48-18',
        sent_mail_time: '2017-09-28 11:07' } ]

Answer 1

您可以使用Object.assign（）：

var _ = require('lodash');

let obj4=[
    { mac_id: '00-17-0d-00-00-30-47-fa',
        sent_mail_time: '2017-09-28 11:07:0' },
    { mac_id: '00-17-0d-00-00-30-48-18',
        sent_mail_time: '2017-09-28 11:07' }
];

let obj3=[
    { mac_id: '00-17-0d-00-00-30-4d-94',
        notif_time: '2017-09-28 10:16:28' },
    { mac_id: '00-17-0d-00-00-30-47-fa',
        notif_time: '2017-09-28 10:14:28' },
    { mac_id: '00-17-0d-00-00-30-49-58',
        notif_time: '2017-09-28 10:26:28' } ];


obj3.forEach(obj3Child => {
    let objtToMerge;
    if (!(objtToMerge = _.find(obj4,function (obj4Child) { return obj4Child.mac_id === obj3Child.mac_id; }))) {
        obj4.push(obj3Child);
    } else {
        Object.assign(objtToMerge, obj3Child);
    }
});

console.log(obj4);

Answer 2

您可以通过以下方式执行此操作

obj4=[ 
      { mac_id: '00-17-0d-00-00-30-47-fa',
        sent_mail_time: '2017-09-28 11:07:0' },
      { mac_id: '00-17-0d-00-00-30-48-18',
        sent_mail_time: '2017-09-28 11:07' }
     ];

obj3=[ 
      { mac_id: '00-17-0d-00-00-30-4d-94',
         notif_time: '2017-09-28 10:16:28' },
      { mac_id: '00-17-0d-00-00-30-47-fa',
         notif_time: '2017-09-28 10:14:28' },
      { mac_id: '00-17-0d-00-00-30-49-58',
         notif_time: '2017-09-28 10:26:28' }
   ];
   
let result= _u.groupBy(obj4.concat(obj3), 'mac_id');

result = Object.keys(result).map(e => Object.assign({}, ...result[e]));
console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/2.4.1/lodash.min.js"></script>
<script>
_u = _.noConflict(); // lets call ourselves _u
</script>

Answer 3

另一种方式

// merge objs
merged = obj3.concat(obj4).map( (item,index,arr) => {
    let duplicates = arr.filter( v => v.mac_id == item.mac_id  )
    return Object.assign(...duplicates)
})

// remove duplicates
merged =  [...new Set(merged)] 
console.log(merged)

合并具有不同长度，键和值的两个对象

3 个答案: