锁定样本错误

Question

我在书Programming in C# Exam Ref 70-483中找到了线程死锁样本，根据我的理解，理论上并不总是会导致死锁：

public static void Main()
        {

            object lockA = new object();
            object lockB = new object();

            var up = Task.Run(() =>
            {
                lock (lockA)
                {
                    Thread.Sleep(1000);
                    lock (lockB)
                    {
                        Console.WriteLine("LockedAandB  " + Thread.CurrentThread.ManagedThreadId);
                    }
                }
            });

            lock (lockB)
            {
                Thread.Sleep(1000); // Should be added. No in original sample
                lock (lockA)
                {
                    Console.WriteLine("LockedBandA " + Thread.CurrentThread.ManagedThreadId);
                }
            }
            up.Wait();

            Console.WriteLine("done");
            Console.ReadLine();


        }

要做到最好，它永远不会在我的机器中出现死锁，因为主线程太快而无法同时锁定并释放它们。如果我错了，请纠正我。

要使此示例变为死锁，我们还需要在Thread.Sleep(1000);行之后的主线程中添加lock(lockB)。我没错？