分别在列phone_number和phone_no的两个表格中
我必须比较它们但是
在phone_no个数字中带有前缀23
并且在phone_number中他们没有前缀
如何比较它们忽略前缀？
第一张表
+------------------+-------------+------+-----+-------------------+----------------+
| Field | Type | Null | Key | Default | Extra |
+------------------+-------------+------+-----+-------------------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| name | text | NO | | NULL | |
| password | text | NO | | NULL | |
| email | text | NO | | NULL | |
| phone_no | text | NO | | NULL | |
| checked_by_admin | int(11) | NO | | 1 | |
| date | timestamp | NO | | CURRENT_TIMESTAMP | |
| download | int(11) | NO | | 1 | |
| sendto | text | YES | | NULL | |
| meet | timestamp | YES | | NULL | |
| note | longtext | NO | | NULL | |
| sec | int(11) | NO | | 1 | |
| alt_phone | text | NO | | NULL | |
| work | text | NO | | NULL | |
| company | text | NO | | NULL | |
| reg_by | text | NO | | NULL | |
| op_status | text | NO | | NULL | |
| lang | varchar(15) | NO | | NULL | |
| deposit_by | varchar(30) | NO | | NULL | |
| list_name | text | NO | | NULL | |
| web | int(11) | YES | | NULL | |
+------------------+-------------+------+-----+-------------------+----------------+
第二张表
`
+-------------------------+------------------------------------------------------------------+------+-----+-------------------+-----------------------------+
| Field | Type | Null | Key | Default | Extra |
+-------------------------+------------------------------------------------------------------+------+-----+-------------------+-----------------------------+
| lead_id | int(9) unsigned | NO | PRI | NULL | auto_increment |
| entry_date | datetime | YES | | NULL | |
| modify_date | timestamp | NO | | CURRENT_TIMESTAMP | on update CURRENT_TIMESTAMP |
| status | varchar(6) | YES | MUL | NULL | |
| user | varchar(20) | YES | | NULL | |
| vendor_lead_code | varchar(20) | YES | | NULL | |
| source_id | varchar(50) | YES | | NULL | |
| list_id | bigint(14) unsigned | NO | MUL | 0 | |
| gmt_offset_now | decimal(4,2) | YES | MUL | 0.00 | |
| called_since_last_reset | enum('Y','N','Y1','Y2','Y3','Y4','Y5','Y6','Y7','Y8','Y9','Y10') | YES | MUL | N | |
| phone_code | varchar(10) | YES | | NULL | |
| phone_number | varchar(18) | NO | MUL | NULL | |
| title | varchar(4) | YES | | NULL | |
| first_name | varchar(30) | YES | | NULL | |
| middle_initial | varchar(1) | YES | | NULL | |
| last_name | varchar(30) | YES | | NULL | |
| address1 | varchar(100) | YES | | NULL | |
| address2 | varchar(100) | YES | | NULL | |
| address3 | varchar(100) | YES | | NULL | |
| city | varchar(50) | YES | | NULL | |
| state | varchar(2) | YES | | NULL | |
| province | varchar(50) | YES | | NULL | |
| postal_code | varchar(10) | YES | MUL | NULL | |
| country_code | varchar(3) | YES | | NULL | |
| gender | enum('M','F','U') | YES | | U | |
| date_of_birth | date | YES | | NULL | |
| alt_phone | varchar(12) | YES | | NULL | |
| email | varchar(70) | YES | | NULL | |
| security_phrase | varchar(100) | YES | | NULL | |
| comments | varchar(255) | YES | | NULL | |
| called_count | smallint(5) unsigned | YES | | 0 | |
| last_local_call_time | datetime | YES | MUL | NULL | |
| rank | smallint(5) | NO | MUL | 0 | |
| owner | varchar(20) | YES | MUL | | |
| entry_list_id | bigint(14) unsigned | NO | | 0 | |
+-------------------------+------------------------------------------------------------------+------+-----+-------------------+-----------------------------+
`
答案 0 :(得分：0)
您可以使用MID（）函数删除前两个字符。 用这种方式进行比较：
where MID(phone_number, 3, 20) = phone_no
答案 1 :(得分：0)
在比较子句中使用SUBSTR函数：
...
WHERE SUBSTR(table1.phone_no, 3) = table2.phone_number