Question

很好的。我正在研究一个过度规范化的数据库，该程序运行我们没有在内部构建的程序。我们需要从不同的表中提取数据以使其工作。当我运行以下查询时，它会导致：

消息4104，级别16，状态1，行14多部分标识符＆＃34; dbo.db_record.db_record_id＆＃34;无法受约束。

我已经调查了这个，我找不到错误的原因，并试图弄清楚我可以做些什么来解决这个问题。

USE [Acuity_Train]

select p.provider_identity,
    p.provider_type,
    p.provider_name,
    p.NPI,
    t.taxonomy_code,
    udf.user_field_data_09 AS [Medicaid #]

 from provider p

 --This join links provider data to taxonomy table for taxonomy code select above
LEFT OUTER JOIN dbo.provider_taxonomy prvt 
             ON prvt.provider_identity = p.provider_identity
INNER JOIN dbo.taxonomy t 
        ON t.taxonomy_identity = prvt.taxonomy_identity

-- This allows for access to medicaid ID #
LEFT OUTER JOIN v_provider_network_affiliation vpna
             ON vpna.key2 = p.provider_identity
            AND vpna.key1 in ('55', '56')
LEFT OUTER JOIN user_field_data AS udf
             ON udf.table_code='PRNW' 
            AND udf.key1=vpna.provider_affiliation_identity 

-- Next 3 Joins needed to access company.company_code
LEFT OUTER JOIN dbo.provider_affiliation praf
             ON praf.db_record_id_child = dbo.db_record.db_record_id
LEFT OUTER JOIN dbo.db_record AS dbr_parent 
             ON praf.db_record_id_parent = dbr_parent.db_record_id  
LEFT OUTER JOIN company 
             ON dbr_parent.key1 = company.company_identity 

Where company.company_code in ('Prestige', '114', '115', '148', '181')

Answer 1

你有... ...

LEFT OUTER JOIN dbo.provider_affiliation praf
         ON praf.db_record_id_child = dbo.db_record.db_record_id

此时您尚未介绍dbo.db_record，因此它不知道您想加入的内容。

Answer 2

错过了一个加入步骤，需要在这里找到另一张桌子。

LEFT OUTER JOIN dbo.db_record 
             ON p.provider_identity = dbo.db_record.key1 
            AND dbo.db_record.table_code = 'PROV' 
LEFT OUTER JOIN dbo.provider_affiliation praf
             ON praf.db_record_id_child = dbo.db_record.db_record_id
LEFT OUTER JOIN dbo.db_record AS dbr_parent 
             ON praf.db_record_id_parent = dbr_parent.db_record_id  
LEFT OUTER JOIN company 
             ON dbr_parent.key1 = company.company_identity

SQL查询返回模糊错误

2 个答案: