Question

抱歉，我刚刚更改了这个问题：我想知道在我的阵列中有多少次我有“橙色”字样。在这个例子中，“橙色”＆gt; 4次。

MyArray = [{
    fruit1: "Orange is blabla",
    fruit2: "Apple blabla",
    fruit3: "blabla Banana",
    color1: "ORANGE"
}, {
    fruit4: "blabla Orange",
    fruit5: "Apple",
    fruit6: "Banana",
    color2: "orange blabla"
}];

var newArr = MyArray.filter(function (item) {
    return _.values(item.xxx === "orange";
});

Answer 1

您可以通过以下方式执行此操作

let MyArray = [{fruit1:"Orange", fruit2:"Apple", fruit3:"Banana", color1:"ORANGE"},{fruit4:"Orange", fruit5:"Apple", fruit6:"Banana", color2:"orange"}];

let result = MyArray.reduce((a, b) => {
    for(let key of Object.keys(b)){
        let re = /orange/gi;
        if(b[key].match(re) != null){
            a++;
        }
    }
    return a;
}, 0);

console.log(result);

Answer 2

MyArray = [{
    fruit1: "Orange is blabla",
    fruit2: "Apple blabla",
    fruit3: "blabla Banana",
    color1: "ORANGE"
}, {
    fruit4: "blabla Orange",
    fruit5: "Apple",
    fruit6: "Banana",
    color2: "orange blabla"
}];

var totalOrange = 0;

MyArray.map(function(item) {
  for (var key in item) {
    if (item[key].toLowerCase().indexOf('orange') >= 0) {
      totalOrange++;
    }
  }
});
console.log(totalOrange);

Answer 3

您可以这样做： -

tableView.separatorStyle = UITableViewCellSeparatorStyleNone;

Answer 4

使用ES6，您可以使用展开式语法...和Object.values来执行此操作。

var MyArray = [{ fruit1: "Orange is blabla", fruit2: "Apple blabla", fruit3: "blabla Banana", color1: "ORANGE" }, { fruit4: "blabla Orange", fruit5: "Apple", fruit6: "Banana", color2: "orange blabla" }]

var count = [].concat(...MyArray.map(Object.values))
	      .filter(e => e.toLowerCase().includes('orange'))
              .length;
              
console.log(count)

Answer 5

我想这样的事情可能有用。你可以在一个大循环中做到这一点，使它稍快一些，但这种形式更具可读性。

const amountOfOranges = MyArray
    // transform each object into an array of its values
    .map( Object.values )
    // remove all values not named 'orange'
    .map( ary => ary.filter( value => value === 'orange' ) )
    // replace all arrays by their length
    .map( ary => ary.length )
    // sum the results
    .reduce( ( x, y ) => x + y, 0 );

Answer 6

var MyArray = [{fruit1:"Orange", fruit2:"Apple", fruit3:"Banana", color1:"ORANGE"},{fruit4:"Orange", fruit5:"Apple", fruit6:"Banana", color2:"orange"}];

var count = 0;
MyArray.map(function(item,index){
    Object.keys(item).map(function(key){
        if(item[key].toLowerCase().indexOf('orange') >= 0){
            count++;
        }
    });
});
console.log(count);

计算每个数组对象的值

6 个答案: