Question

我试图对包含状态键的对象进行排序，该状态键具有＆＃34; online＆＃34;，＆＃34;离线＆＃34;，＃34;忙碌＆＃34; ，所以只是想以一种所有＆＃34; online＆＃34;将出现在顶部，然后是＆＃34;忙碌＆＃34;然后＆＃34;离线＆＃34;

var arr = [{_id: "58e21249", name: "test2", status: "offline"},
           {_id: "58e1249", name: "test3", status: "online"},
           {_id: "58qwe49", name: "test21", status: "offline"},
           {_id: "58ed49", name: "test212", status: "online"},
           {_id: "58ee49", name: "test23", status: "offline"},
           {_id: "58xe49", name: "test12", status: "online"},
           {_id: "5849", name: "test2323", status: "busy"},
           {_id: "58er49", name: "test2121", status: "busy"}];

arr.sort(function(first, second) {
   if (second.status == "online") return 1;

 });

console.log(arr);

这将仅返回我的状态：＆＃34; online＆＃34;在顶端。感谢

Answer 1

试试这个：

＆＃13;

var arr = [{_id: "58e21249", name: "test2", status: "offline"},
           {_id: "58e1249", name: "test3", status: "online"},
           {_id: "58qwe49", name: "test21", status: "offline"},
           {_id: "58ed49", name: "test212", status: "online"},
           {_id: "58ee49", name: "test23", status: "offline"},
           {_id: "58xe49", name: "test12", status: "online"},
           {_id: "5849", name: "test2323", status: "busy"},
           {_id: "58er49", name: "test2121", status: "busy"}];
           
 var statusOrder = ["online", "busy", "offline"];
 
 arr = arr.sort(function(a, b) { 
     return statusOrder.indexOf(a.status) - statusOrder.indexOf(b.status);
 });

 console.log(arr);

＆＃13;

甚至更短的ECMAScript6：

＆＃13;

var arr = [{_id: "58e21249", name: "test2", status: "offline"},
           {_id: "58e1249", name: "test3", status: "online"},
           {_id: "58qwe49", name: "test21", status: "offline"},
           {_id: "58ed49", name: "test212", status: "online"},
           {_id: "58ee49", name: "test23", status: "offline"},
           {_id: "58xe49", name: "test12", status: "online"},
           {_id: "5849", name: "test2323", status: "busy"},
           {_id: "58er49", name: "test2121", status: "busy"}];
           
 var statusOrder = ["online", "busy", "offline"];
 
 arr = arr.sort((a, b) => statusOrder.indexOf(a.status) - statusOrder.indexOf(b.status));

 console.log(arr);

＆＃13;

Answer 2

var statusOrder = ["online", "offline", "busy"];
arr.sort(function(first, second) {
    return statusOrder.indexOf(first.status) < statusOrder.indexOf(second.status);
});

Javascript对键值的对象数组进行排序

2 个答案: