Question

该程序非常简单。提示员工的工资单，工作时间，付费代码等。

// Project Name: Lab Assignment 3
// Programmer Name: Trenton Covieo
// Date Written: 9/18/2017
// Description: This program will calculate employee pay based on  paycode and hours provided by the employee
#include <iostream>
#include <string>
#include <iomanip>
using namespace std;
//  Begin main Function Definition    
    int main()    
    {
        //intialization
        char paycode;
        string employee_number;
        int hours;
        const double min_wage = 8.90;
        double pay_rate;
        double calc_pay;
        char again;
        int employee_num = 0;

        //Diplay identifcation on screen        
        cout << "Lab Assignment 3"<< endl; 
        cout << "programmed by Trenton Covieo" << endl << endl;

        //Prompts for exmployee number      
        do{
            cout << "Enter employee number: ";
            cin >> employee_number;
            // prompts for/ determines paycode and payrate

            cout <<"Enter Paycode: ";
            cin >> paycode;
            switch (paycode)
            {
                case 'M':
                pay_rate = min_wage;
                break;

                case 'O':
                pay_rate = min_wage + 1;
                break;

                case 'T':
                pay_rate = min_wage + 2; 
                break;

                case 'm':
                pay_rate = min_wage;
                break;

                case 'o':
                pay_rate = min_wage + 1;
                break;

                case 't':
                pay_rate = min_wage + 2;
                break;

                // An incorrect code was entered
                default: 
                pay_rate = 0;
                cout << "You did not enter a valid paycode!" << endl;
                break;
            }
            // Prompts for hours worked

            cout << "Enter hours worked: ";
            cin >> hours;

            //calculates pay based upon hours entered including overtime
            if (hours <=40)  
                calc_pay = pay_rate * hours;
            else if (hours > 40)
                calc_pay = (pay_rate* 40) + pay_rate * (hours-40) * 1.5;

            //outputs information entered       
            cout << "Employee#: " << employee_number << endl;
            cout << "Pay Rate $: " << fixed
                 << setprecision(2)<< pay_rate  << endl;
            cout << "Hours Worked: "
                 << fixed << setprecision(2) << hours <<  endl;
            cout << "Total Pay: " << fixed << setprecision(2) << calc_pay 
                 << endl;

            // prompt for another employeee
            cout<< "Do you want to enter another employee? (Y/N) ";
            cin >> again;
        }while (again =='Y' || again =='y') ;

        /* This is the part that I can't seem to figure out.
           I have anoter Do-While loop that says
           whenever the paycode = 'm' it will add 1 to employee_num.
           It works fine when i have one condition,
           but if i try two (both 'M' and 'm') the cout won't work. */
        do
        {    employee_num++;
        }while (paycode == 'm'|| paycode =='M') ;
        cout <<"Number of Employees Processed: " << employee_num << endl;

Answer 1

雅，因为do while循环处于无限循环

使用if语句而不是

时执行

if (paycode == 'm'|| paycode =='M') {
      employee_num++;
}

cout <<"Number of Employees Processed: " << employee_num << endl;

Answer 2

您的问题是由于您在第二个循环中未更改paycode而导致的无限循环。一旦检测到'm'或'M'，它就会一直持续。

简单地说：

   do
    {    employee_num++;
    }while (paycode == 'm'|| paycode =='M') ;

到

    if (paycode == 'm'|| paycode =='M') 
    {    employee_num++;
    }

将解决这个直接问题。

但是，我得到的印象是，您打算使用付费代码“mM”来计算员工数量。通过在前一个循环中进行计数，可以更优雅地实现这一点。

    do{
        /* ... */
        switch (paycode)
        {
            case 'M':
            case 'm':
                employee_num++;
                pay_rate = min_wage;
                break;

        /* ... combining O&o, T&t */
            default:
                /* ... */
        }

        // prompt for another employeee
        cout<< "Do you want to enter another employee? (Y/N) ";
        cin >> again;
    } while (again =='Y' || again =='y');

    cout <<"Number of Employees Processed: " << employee_num << endl;

    /* ... */

或者，如果您想计算所有员工，如变量的命名和循环后的输出所示，
在第一个循环中无条件地执行。

    do{
        /* ... */
        switch (paycode)
        {
                /* ... */
        }
        employee_num++;

        // prompt for another employeee
        cout<< "Do you want to enter another employee? (Y/N) ";
        cin >> again;
    } while (again =='Y' || again =='y');

    cout <<"Number of Employees Processed: " << employee_num << endl;

    /* ... */

如何在do while循环的多个条件下显示此输出

2 个答案: