Question

这是一个我无法解决的两部分问题。第一部分要求整个对象属于Theo＆＃39; Theo＆＃39;以某种方式删除。第二部分需要通过编辑属于＆＃39; Lorie＆＃39;的属性值之一来更改对象。这是数组和说明：

var employees = [{
    "firstName": "Von",
    "lastName": "Budibent",
    "email": "vbudibent0@163.com",
    "department": "Sales"
}, {
    "firstName": "Catherina",
    "lastName": "Swalowe",
    "email": "cswalowe1@example.com",
    "department": "Engineering"
}, {
    "firstName": "Theo",
    "lastName": "Trill",
    "email": "ttrill2@sina.com.cn",
    "department": "Services"
}, {
    "firstName": "Elsy",
    "lastName": "McCrorie",
    "email": "emccrorie3@netscape.com",
    "department": "Legal"
}, {
    "firstName": "Lorie",
    "lastName": "Handsheart",
    "email": "lhandsheart4@fotki.com",
    "department": "Research and Development"
}]

/* Create a function called 'employeeUpdater'. employeeUpdater will loop 
over the array above and perform the following:
  1. If employee's first name is Theo, remove that employee because he just 
got fired.
  2. If the employee's first name is Lorie, change her department to 'HR'.
  3. Return the updated employee array. */

我必须要做的就是以下内容：

var employeeUpdater = () => {
  for (let i = 0; i < employees.length; i++) {
    if (employees[i] = 'Theo') {
      employees.remove(employees[i]);
    } else if (employees[i] = 'Lorie') {
      employees.department = 'HR';
    }
  } return employees;
}

代码

有问题

Answer 1

Javascript数组没有名称为remove的方法，而是需要使用Array#splice方法删除项目。但我可以建议这个解决方案。

首先使用Array#filter排除名称为Theo的对象，然后使用Array#map或Array#forEach迭代数组，找到名称为{{1}的对象并改变它的部门a。

＆＃13;

Lorie

＆＃13;

Answer 2

你可以用splice（）：

来做

var employeeUpdater = () => {
  for (let i = 0; i < employees.length; i++) {
    if (employees[i].firstName == 'Theo') {
      employees.splice(i, 1);
      i--;
    } else if (employees[i].firstName == 'Lorie') {
      employees[i].department = 'HR';
    }
  }
}return employees;

Answer 3

在数组中引用对象的一个棘手问题是你需要记住你必须用数组索引号引用它们，然后像employees [2]那样引用对象名.firstName就是你引用Theo的方式。此外，拼接方法最适合删除如上所述的数组。

我相信您尝试编写的代码如下所示：

var employeeUpdater = () => {
  for (let i = 0; i < employees.length; i++) {
    if (employees[i].firstName === 'Theo') {
      employees.splice(i, 1);
    } else if (employees[i].firstName === 'Lorie') {
      employees[i].department = 'HR';
    }
  } return employees;
}

Answer 4

您应该学习以面向对象的方式编程。也许这会有所帮助：

＆＃13;

//<![CDATA[
var pre = onload;
onload = function(){
if(pre)pre(); // change pre var name if using technique on other pages

var employees = [{
  firstName:'Von',
  lastName: 'Budibent',
  email:'vbudibent0@163.com',
  department:'Sales'
}, {
  firstName:'Catherina',
  lastName:'Swalowe',
  email:'cswalowe1@example.com',
  department:'Engineering'
}, {
  firstName:'Theo',
  lastName:'Trill',
  email:'ttrill2@sina.com.cn',
  department:'Services'
}, {
  firstName:'Elsy',
  lastName:'McCrorie',
  email:'emccrorie3@netscape.com',
  department:'Legal'
}, {
  firstName:'Lorie',
  lastName:'Handsheart',
  email:'lhandsheart4@fotki.com',
  department:'Research and Development'
}];
function EmployeeHandler(employeeArray){
  this.employees = employeeArray;
  this.removeByFirstName = function(firstName, caseSensitive){
    var emp = this.employees;
    var rx = caseSensitive ? new RegExp(firstName) : new RegExp(firstName, 'i');
    for(var i=0,l=emp.length; i<l; i++){
      if(emp[i].firstName.match(rx)){
        this.employees.splice(i, 1);
        return this;
      }
    }
    return false;
  }
  this.removeByLastName = function(lastName, caseSensitive){
    var emp = this.employees;
    var rx = caseSensitive ? new RegExp(lastName) : new RegExp(lastName, 'i');
    for(var i=0,l=emp.length; i<l; i++){
      if(emp[i].lastName.match(rx)){
        this.employees.splice(i, 1);
        return this;
      }
    }
    return false;
  }
  this.getByFirstName = function(firstName, caseSensitive){
    var emp = this.employees;
    var rx = caseSensitive ? new RegExp(firstName) : new RegExp(firstName, 'i');
    for(var i=0,l=emp.length,em; i<l; i++){
      em = emp[i];
      if(em.firstName.match(rx)){
        return em;
      }
    }
    return false;
  }
  this.getByLastName = function(lastName, caseSensitive){
    var emp = this.employees;
    var rx = caseSensitive ? new RegExp(lastName) : new RegExp(lastName, 'i');
    for(var i=0,l=emp.length,em; i<l; i++){
      em = emp[i];
      if(em.lastName.match(rx)){
        return em;
      }
    }
    return false;
  }
}

var eh = new EmployeeHandler(employees);
var bb = eh.removeByFirstName('Theo').getByLastName('Budibent');
bb.department = 'Intelligent Design';
console.log(eh.employees); console.log(bb); console.log(eh.employees);

}
//]]>

＆＃13;

Answer 5

试试这个

var editedEmployees = employees
.filter(emp => emp.firstName !== 'Theo')
.map((emp) => {emp.department = emp.firstName === 'Lorie' ? 'HR' : 
emp.department; return emp;});

Answer 6

如果您希望使用lodash，则可以使代码更易于阅读。

所以你的脚本应该是这样的：

var _ = require('lodash');
/* Remove element */
_.remove(employees, function (employee) { return employee.firstName === 'Theo'; });
/* Get element to change */
var employee = _.find(employees,function (employee) { return employee.firstName === 'Lorie'; });
/* Change element */
employee.firstName = 'HR';
/* Right now employees store the right result */

如何更改数组中的多个对象？

6 个答案: