使用spark(py)从amazon redshift读取数据时出错在请求存储桶的位置时必须指定存储桶名称参数

时间:2017-09-28 03:27:05

标签: apache-spark amazon-redshift pyspark-sql

你能帮助我使用spark + redshift +数据砖驱动程序,读取数据吗?

现在我收到错误调用read方法。下面是我的一段代码。

df = spark.read.format("com.databricks.spark.redshift")
    .option("url",redshifturl).option("dbtable", "PG_TABLE_DEF")
    .option("tempdir","s3n://KEY_ID:SECRET_KEY_ID@/S2_BUCKET_NAME/TEMP_FOLDER_UNDER_S3_BUCKET/")
    .option("aws_iam_role","AWS_IAM_ROLE").load()

以下是我收到的错误日志

    IllegalArgumentException: u"The bucket name parameter must be specified when requesting a bucket's location"
---------------------------------------------------------------------------
IllegalArgumentException                  Traceback (most recent call last)
<command-3255625043609925> in <module>()
----> 1 df = spark.read   .format("com.databricks.spark.redshift")   .option("url", redshifturl)   .option("dbtable", "pg_table_def")   .option("tempdir", "s3n://AKIAJXVW3IESJSQUTCUA:kLHR85WfcieNrd7B7Rm/1FK1JU4NeKTrpe8BkLbx@/weatherpattern/temp/")   .option("aws_iam_role", "arn:aws:iam::190137980335:user/user1")  .load()

/databricks/spark/python/pyspark/sql/readwriter.py in load(self, path, format, schema, **options)
    163             return self._df(self._jreader.load(self._spark._sc._jvm.PythonUtils.toSeq(path)))
    164         else:
--> 165             return self._df(self._jreader.load())
    166 
    167     @since(1.4)

/databricks/spark/python/lib/py4j-0.10.4-src.zip/py4j/java_gateway.py in __call__(self, *args)
   1131         answer = self.gateway_client.send_command(command)
   1132         return_value = get_return_value(
-> 1133             answer, self.gateway_client, self.target_id, self.name)
   1134 
   1135         for temp_arg in temp_args:

/databricks/spark/python/pyspark/sql/utils.py in deco(*a, **kw)
     77                 raise QueryExecutionException(s.split(': ', 1)[1], stackTrace)
     78             if s.startswith('java.lang.IllegalArgumentException: '):
---> 79                 raise IllegalArgumentException(s.split(': ', 1)[1], stackTrace)
     80             raise
     81     return deco

IllegalArgumentException: u"The bucket name parameter must be specified when requesting a bucket's location"

我认为s3n路径存在一些问题,但我提供的方式.option方法看起来是正确的,我的真实凭据。

任何建议都将不胜感激。

由于

伊姆兰:)

-

1 个答案:

答案 0 :(得分:0)

您的路径网址不正确,

格式应该是,

  

S3N:// ACCESSKEY:秘密密钥@桶/路径/到/温度/ DIR

df = spark.read.format("com.databricks.spark.redshift")
    .option("url",redshifturl).option("dbtable", "PG_TABLE_DEF")
    .option("tempdir","s3n://KEY_ID:SECRET_KEY_ID@S2_BUCKET_NAME/TEMP_FOLDER_UNDER_S3_BUCKET/")
    .option("aws_iam_role","AWS_IAM_ROLE").load()

<强>文档

https://github.com/databricks/spark-redshift

希望它有所帮助。