Question

我是python和编程世界的新手。达到目的。当我运行这个代码并输入输入让我说鸡，它会回复为两腿动物。但我不能得到两个字的回复，就像空间猴子之间有空间（虽然它出现在我的字典中）所以我该如何解决呢？

我的字典：example.py

dictionary2 = {
    "chicken":"chicken two leg animal",
    "fish":"fish is animal that live under water",
    "cow":"cow is big vegetarian animal",
    "space monkey":"monkey live in space",

我的代码：test.py

from example import *

print "how can i help you?"
print

user_input = raw_input()

print
print "You asked: " + user_input + "."
response = "I will get back to you. "

input_ls = user_input.split(" ")
processor = {
    "dictionary2":False,
    "dictionary_lookup":[]
}
for w in input_ls:

    if w in dictionary2:
        processor["dictionary2"] = True
        processor["dictionary_lookup"].append(w)

if processor["dictionary2"] is True:
    dictionary_lookup = processor["dictionary_lookup"][0]
    translation = dictionary2[dictionary_lookup]
    response = "what you were looking for is: " + translation

print
print "Response: " + response

Answer 1

您的代码存在的问题是当您使用for w in input_ls时，您传递的内容是＆＃34;空间猴子＆＃34;，它寻找空间，然后它寻找猴子。如果您希望使用此特定脚本获得所需结果，则它看起来像这样

print "how can i help you?"
print

user_input = raw_input()

print
print "You asked: " + user_input + "."
response = "I will get back to you. "

input_ls = user_input
processor = {
    "dictionary2":False,
    "dictionary_lookup":[]
}

if input_ls in dictionary2:
    processor["dictionary2"] = True
    processor["dictionary_lookup"].append(input_ls)

if processor["dictionary2"] is True:
    dictionary_lookup = processor["dictionary_lookup"][0]
    translation = dictionary2[dictionary_lookup]
    response = "what you were looking for is: " + translation

print
print "Response: " + response

请注意，我还将input_ls = user_input.split(" ")更改为input_ls = user_input，因为这会将您的字符串转换为单个字词的数组，如果您使用的话，这些字词将无法返回您正在查找的字词。\ n＆＃39}重新尝试查找特定的短语而不是单个单词，并在此处进行了这一重要更改

if input_ls in dictionary2:
    processor["dictionary2"] = True
    processor["dictionary_lookup"].append(input_ls)

- 编辑 -

我不得不出去工作，但现在我回家了，我可以更好地解决这个问题。当试图使用字典来实现这个目标时，我会如何做到这一点。

dictionary2 = {
    "red":"the color red",
    "blue":"fish is animal that live under water",
    "red and blue":"these colors make blue",
    "blue and yellow":"these colors make green"
}
user_input = raw_input('what would you like?\t')
user_input = user_input.split(' ')
print
for word in user_input:
    for key,val in dictionary2.iteritems():
        if word in key:
            print '%s: %s' % (key,val)

尝试迭代字典时，您需要使用以下任一项：
dictionary2.iteritems（）用于key和val
dictionary2.iterkeys（）为你的钥匙
你的值的dictionary2.itervalues（）

Answer 2

即使选择了答案，我也会重新回答我的答案，因为这是一个有趣的问题，而且我在给定时间内接近公平的解决方案。

这个答案可以带问人类问题，而不仅仅是单词。

虽然，对于真正的机器学习nltk是更好的选择。首先，我们可以使用下面的内容。

它使用内置库difflib来匹配字典键的问题，并确定哪个具有更高的概率。

警告：未实现异常处理。它只会获得最大可能的匹配。

然后我们使用re从回答中删除密钥中的单词并将所有内容重新组合在一起。这比仅显示键值提供了更自然的答案。

import re
from difflib import SequenceMatcher

def similarity(a, b):
    return SequenceMatcher(None, a, b).ratio()

dictionary2 = {
    "chicken":"chicken two leg animal",
    "fish":"fish is animal that live under water",
    "cow":"cow is big vegetarian animal",
    "space monkey":"monkey live in space",}

user_input = raw_input("User Question:")

#Check which key has greater probability match
similarity_list = []
for i in dictionary2.keys():
    similarity_list.append((i,similarity(user_input,i))) 

key_match = max(similarity_list, key=lambda x:x[1])

uin = ('|'.join(key_match[0].split()))
p = re.compile(r"\b(" + uin + ")\\W", re.I)
ans = p.sub('', dictionary2[key_match[0]])
print "answer: {} {}".format(key_match[0], ans)

结果

Python 2.7.9 (default, Dec 10 2014, 12:24:55) [MSC v.1500 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> ================================ RESTART ================================
>>> 
User Question:what is a chicken?
answer: chicken two leg animal
>>> ================================ RESTART ================================
>>> 
User Question:Where does space monkey live?
answer: space monkey live in space
>>> ================================ RESTART ================================
>>> 
User Question:Where does fish live?
answer: fish is animal that live under water
>>> ================================ RESTART ================================
>>> 
User Question:what is a cow?
answer: cow is big vegetarian animal
>>>

Answer 3

你需要解释你的目的，以获得更好的帮助。在你的情况下，你似乎只对查找单词感兴趣，然后这段代码就足够了。请注意.format（）语法可以彻底清理代码。

更新代码：现在使用输入中找到的组合创建列表。然而，这可能需要修改以满足需求。

dictionary2 = {
"chicken":"chicken two leg animal",
"fish":"fish is animal that live under water",
"cow":"cow is big vegetarian animal",
"space monkey":"monkey live in space"}

print("how can i help you?")
user_input = raw_input()
print("You asked: {}.".format(user_input))

split = user_input.split(" ")
combos = [' '.join(split[x:y]) for x in range(len(split)) for y in range(len(split)+1) if ' '.join(split[x:y]) != ""]

# Create an empty dictionary to insert found item
response = {}

for item in combos:
    if dictionary2.get(item):
        response[item] = "what you were looking for is: {}.".format(dictionary2[item])

# If dictionary is empty do this
if not response:
    print("Response: I will get back to you!")

# If not, loop over keys(k) and values(v) and print them with an index(ind)
for ind, (k,v) in enumerate(response.iteritems()):
    print("Response {}: {} ({})".format(ind+1, v, k))

在字典中搜索2个单词键

3 个答案: