Question

我应该创建一个程序，使用用户的输入创建平均测试分数。我还需要确保当用户说“结束”而不是输入分数时，程序会有中断并且会给用户提供结果。但是，我无法使程序正常运行并想要一些输入。

#!/usr/bin/env python3

#display a welcome message
print("The test Scores program")
print()
print("Enter end to stop input") #change from 999 to end
print("========================")
print()

#variables
counter = 0
score_total = 0
test_score = 0

choice = "y"

while choice.lower():
    while True:
        test_score =input("Enter test score: ")

        if test_score == "end":
            break
        elif (test_score >= 0) and (test_score <= 100):
            score_total += test_score
            counter += 1
        else:
            print("Test score must be from 0 through 100. Try again>")

    #calculate average score
    average_score = round(score_total / counter)

    #display result
    print("=======================")
    print("Total Score: ", score_total)
    print("Average Score: ", average_score)
    print()

    #see if user wants to continue
    choice = input("Continue (y/n)? ")
    print()

print("Bye")

Answer 1

当您执行(test_score >= 0) and (test_score <= 100)时，您正在比较字符串和int，当您将输入与数字进行比较时，您希望将输入转换为int。

试试这个：

    test_score =input("Enter test score: ")

    if test_score == "end":
        break
    elif (int(test_score) >= 0) and (int(test_score) <= 100):
        score_total += int(test_score)
        counter += 1
    else:
        print("Test score must be from 0 through 100. Try again>")

我只是在将test_score与数字进行比较时将其转换为int。

Answer 2

已经很晚了，但这是给碰巧遇到相同问题的任何人的。您可以尝试从Test_score = input（“ Enter test score：”）:)中分离出'int'

while True:
        test_score = input("Enter test score: ")
        if test_score == 'end':
            break
        test_score = int(test_score)
        if 0 <= test_score <= 100:
            score_total += test_score
            counter += 1
    
        else:
            print(
                "Test score must be from 0 through 100. Score discarded. Try again."
            )

测试成绩计划 - Python

2 个答案: