Question

请问为什么代码只为前三次迭代提供最小和最大的正确输出？

我前三次迭代的输出正常工作。最小和最大变量被锁存到这些值，并且不会根据新输入进行更新。剩余的计算（总和，计数和平均值）工作正常。

[enter image description here][1]
count= 0
sum=0
average=0
minimal=None
maximum=None
while True:
    number=raw_input("Enter a number: ")
    try:
        if (number=='done'):
            break
        else:
            count=count+1
            sum=sum+float(number)
            if minimal==None:
                minimal=float(number)
                maximum=float(number)
            else:
                minimal=min(number,minimal)
                maximum=max(number,maximum)
                print maximum
                print minimal
            average=sum/count
            #print ("Calc done")
    except:
        print ("Invalid input")
print("Count: %d, Sum=%d and Average=%d" %(count,sum,average))
print("smallest number is %d" %minimal)
print("largest number is %0.2f" %float(maximum))

Answer 1

在您的函数调用min(number,minimal)和max(number,maximum)中，您不会将number强制转换为浮点数。这必须以minimal完成，maximum是浮点类型。

尝试将参数number替换为float(number)，如下所示：

minimal=min(float(number),minimal)
maximum=max(float(number),maximum)

Answer 2

下面的代码有效。请看差异：

count= 0
sum=0
average=0
minimal=None
maximum=None
while True:
    number=raw_input("Enter a number: ")
    try:
        if (number=='done'):
            break
        else:
            count=count+1
            sum=sum+float(number)
            if minimal==None:
                minimal=float(number)
                maximum=float(number)
            else:
                minimal=min(float(number),minimal)
                maximum=max(float(number),maximum)
                print maximum
                print minimal
            average=sum/count
            #print ("Calc done")
    except:
        print ("Invalid input")
print("Count: %d, Sum=%d and Average=%d" %(count,sum,average))
print("smallest number is %d" %minimal)
print("largest number is %0.2f" %float(maximum))

为什么代码只适用于前三次迭代？

2 个答案: