PHP使用mysql

Question

我的脚本允许用户使用ssh2_exec从远程服务器执行脚本。我在MySQL中设置了一个排队机制，它使用status flag=0执行所有服务器。我当前的代码将更改status flag=1执行脚本，脚本完成后更改status flag=2。但我现在我的代码只按顺序执行。意味着ssh2_exec之后它将转移到下一个服务器。我的所有服务器都有名称，我希望所有具有不同名称的服务器同时执行脚本，有没有办法做到这一点？

testexec.php

$qStatusNotDone = "SELECT status FROM mytable WHERE status = 0";                //status = 0; not done
$rStatusNotDone = mysqli_query($dbConnection, $qStatusNotDone);

if (mysqli_num_rows($rStatusNotDone) > 0){

    //for each server that is undone and about to process, we check if it is already processing and handle it accordingly...
    foreach($nextTestArray as $index => $row) {
        $id = $row['MIN(id)'];
        $server = $row['server'];
        $test_script = $row['test_script'];

        echo $id . " " . $server . " " . $test_script . " ";

        //if the server is already processing we skip it        
        if(in_array($server, $serversInProgressArray)){
            echo "This server $server is doing another job, moving on to the next server\n";

        }   
        //otherwise we run the test
        else {
            echo "This server $server is job free, run the test $test_script for this server!\n";
            if ($connection = @ssh2_connect($server, 22)) {
                ssh2_auth_password($connection, $srvrUser, $srvrPassword);

                //set status to in progress and execute the test case
                $qUpdateStatusInProgress = "UPDATE mytable SET status = 1 WHERE id = $id"; //status = 1; in progress
                mysqli_query($dbConnection, $qUpdateStatusInProgress);
                $stream = ssh2_exec($connection, "$executeScript $test_script $server $id");

                //fetch output stream and stderr
                stream_set_blocking($stream, true);
                $stream_out = ssh2_fetch_stream($stream, SSH2_STREAM_STDIO);
                $stream_err = ssh2_fetch_stream($stream, SSH2_STREAM_STDERR);
                while($line = fgets($stream_out)) {flush(); echo $line;}                
                echo "------------------------------------------------\n";
                while($line = fgets($stream_err)) {flush(); echo $line;}
                fclose($stream);    
            }
            //update the table after the test is done
            $qUpdateStatusDone = "UPDATE mytable SET status = 2 WHERE id = $id"; //status = 2; done
            mysqli_query($dbConnection, $qUpdateStatusDone);

        }
    } //end of foreach loop
    mysqli_close($dbConnection);
    unset($dbConnection);
}

else {
    exit("There are no jobs to process, exiting...");
}