我在XAMPP服务器上运行此代码,该服务器连接到db.php
中的数据库。
<?php
require 'db.php';
session_start();
$first_name = $_SESSION['first_name'];
$last_name = $_SESSION['last_name'];
$email = $_SESSION['email'];
$active = $_SESSION['active'];
if(isset($_GET['email']) && !empty($_GET['email']) AND isset($_GET['hash']) && !empty($_GET['hash']))
{
$email = $mysqli->escape_string($_GET['email']);
$hash = $mysqli->escape_string($_GET['hash']);
$mysqli->query("SELECT * FROM users WHERE email='$email' AND hash='$hash' AND active='1'");
if (@@ROWCOUNT <> 1) {
$_SESSION['message'] = "Account has already been activated";
echo '<script type="text/javascript">
window.location = "/html/rtl/profile.php"
</script>';
}
}
我试图在PHP中使用if语句来查看我的MySQL搜索是否返回结果,但它无法正常工作。我该怎么做?
答案 0 :(得分:-1)
试试这个:
$query = $mysqli->query("SELECT * FROM users WHERE email='$email' AND hash='$hash' AND active='1'");
if($query->num_rows<>1) {
//Rest of the code
}