Question

Array包含一些非空数组。我需要获取相应的非空数组并打印数据。例如：数组2的变量为importTroubles-＆gt; troubleMessage我该如何打印？

Array
(
 [0] => stdClass Object
    (
    )

[1] => stdClass Object
    (
    )

[2] => stdClass Object
    (
        [return] => stdClass Object
            (
                [failureMessage] => 
                [importTroubles] => stdClass Object
                    (
                        [kind] => ParseError
                        [rowNumber] => 1
                        [troubleMessage] => Field "number1" has invalid value: "+16046799329". Invalid phone number //need to print this..
                    )

                [keyFields] => number1
                [uploadDuplicatesCount] => 0
                [uploadErrorsCount] => 1
                [warningsCount] => stdClass Object
                    (
                    )

                [callNowQueued] => 0
                [crmRecordsInserted] => 0
                [crmRecordsUpdated] => 2
                [listName] => new camp from CRM1-TargetList-CRM
                [listRecordsDeleted] => 0
                [listRecordsInserted] => 2
            )

    )

[3] => stdClass Object
    (
    )

[4] => stdClass Object
    (
    )

）

我尝试使用这种方法：

foreach($result as $object) {
foreach ($object as $items) {

    if($items !== '')
    {
        foreach ($items as $item) {
            echo "ERROR".$item->troubleMessage;
        }
    }

}
}

感谢您的努力

Answer 1

利用php函数empty（）

更改您的if条件，如下面的代码：

foreach($result as $object) {
 foreach ($object as $items) {
    if( !empty($items) )
    {
        foreach ($items as $item) {
          if( isset($item->troubleMessage) )
          {
            echo "ERROR".$item->troubleMessage;
          }
        }
    }
 }
}

现在只有$items有值时才会回显。

Answer 2

将您的if($items !== '')更改为if(!empty($items))或if($items)或if($items[0])希望有所帮助

Answer 3

如果您只是寻找嵌套在其中的单个特定项目，则不必迭代每个对象。您可以直接参考该项目。

foreach ($your_array as $object) {
    if (isset($object->return->importTroubles->troubleMessage)) {
        echo $object->return->importTroubles->troubleMessage;
    }
}

如果检查是否设置了特定的嵌套对象变量，它将忽略任何空对象。

Answer 4

您可以使用Collection

use Illuminate\Support\Collection;

$collection = new Collection($result);

$items = $collection->filter(function($object) {

    return isset($object->return->importTroubles->troubleMessage);

})->map(function($object) {

    return $object->return->importTroubles->troubleMessage;

});

如何从Array中获取非空数组

4 个答案: