Question

我有一个字符串向量。

Vector <string> myVector;

假设myVector当前有2个字符串。

myVector[0] is "id1|Name1|Age1"
myVector[1] is "id2|Name2|Age2"

现在我想基于分隔符“|”拆分向量中的每个字符串并将结果存储在id，name和age的结构中。

任何人都可以帮忙吗？

Answer 1

类似的东西，你需要检查它

struct{
   unsigned int id;
   std::string name;
   unsigned int age;
}MyStruct;

int main()
{
  std::string line;
  std::vector<std::string> myVector = {"id1|Name1|Age1","id2|Name2|Age2"};
  std::vector<MyStruct> myStruct;
  for (string::const_iterator it = myVector .begin(); it != myVector.end(); it++) 
  {
    vector<std::string> splitLine; 
    while(std::getline(*it,line,'|'))
       splitLine.push_back(line); 

    if (splitLine.size()> 0)
    {
       MyStruct mSt;
       mSt.id = (int)splitLine[0];
       mSt.name = splitLine[1];
       mSt.age= (int)splitLine[2];
       myStruct.push_back(mSt);
    }
  }


   return 0;
}

Answer 2

使用substr（）和find（）很简单。

#include <iostream>
#include <vector>
#include <string>

using namespace std;

struct Person
{
    string m_id;
    string m_name;
    int    m_age;
};

int main()
{
    vector<string> data;
    vector<Person> people;

    data.push_back("id1|Name1|25");
    data.push_back("id2|Name2|35");

    for(int i(0); i < data.size(); ++i){
        size_t idx  = data[i].find("|");
        string id   = data[i].substr( 0, idx);
        string name = data[i].substr(idx+1, data[i].find_first_of("|", idx) + idx - 1);
        string age  = data[i].substr( data[i].find_last_of("|") + 1 );

        Person p = {id, name, stoi(age)};
        people.push_back(p);

    }

    for(int i(0); i < people.size(); ++i)
        cout << people[i].m_id << "  " << people[i].m_name << "  " << people[i].m_age << endl;

    return 0;
}

，输出

id1  Name1  25
id2  Name2  35

基于分隔符拆分字符串向量并将结果存储在结构中

2 个答案: