我如何使用OAuth为Twitter回拨Android?

时间:2011-01-10 06:28:35

标签: android callback twitter twitter-oauth

从过去的5天开始,我正在使用OAuth在Android中搜索twitter的最佳工作代码......我发现了很多。但没有一个1完美运行。我怎么得到一些代码。它的工作,但我有一个问题。我喜欢用String callBack =“?”写的东西。这样我的android浏览器会将我的应用程序重定向到我的应用程序,而不是在认证后停留在那里。如果我没有使用回调并使用 OAuth.OUT_OF_BAND ,那么浏览器会显示一个密码并且不会重定向浏览器我的申请。请帮我告诉我我做错了什么。

我的代码在这里

package com.example.tweeter;

import oauth.signpost.OAuth;
import oauth.signpost.OAuthProvider;
import oauth.signpost.commonshttp.CommonsHttpOAuthConsumer;
import oauth.signpost.commonshttp.CommonsHttpOAuthProvider;
import oauth.signpost.exception.OAuthCommunicationException;
import oauth.signpost.exception.OAuthExpectationFailedException;
import oauth.signpost.exception.OAuthMessageSignerException;
import oauth.signpost.exception.OAuthNotAuthorizedException;

import org.apache.http.client.HttpClient;
import org.apache.http.impl.client.DefaultHttpClient;

import android.app.Activity;
import android.content.Intent;
import android.net.Uri;
import android.os.Bundle;

public class Tweeter extends Activity {

    private String CONSUMER_KEY = "CONSUMER_KEY";
    private String CONSUMER_SECRET = "CONSUMER_SECRET";
    private static final Uri CALLBACK_URI = Uri.parse("PicPuzzle://tkxel");
    private String CALLBACK_URL = "PicPuzzle://tkxel";
    OAuthProvider provider ;
    CommonsHttpOAuthConsumer consumer ;

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        consumer = new CommonsHttpOAuthConsumer(
                CONSUMER_KEY, CONSUMER_SECRET);

        provider = new CommonsHttpOAuthProvider(
                "http://twitter.com/oauth/request_token",
                "http://twitter.com/oauth/access_token",
                "http://twitter.com/oauth/authorize");
        provider.setOAuth10a(true);

        HttpClient client = new DefaultHttpClient();

        String authUrl = "http://www.yahoo.com";
        try {

            //This line work perfect but it not redirect me to my application
            authUrl = provider.retrieveRequestToken(consumer, OAuth.OUT_OF_BAND);

            //I want to send a calll back but It give exception
            ///***  authUrl = provider.retrieveRequestToken(consumer, CALLBACK_URI.toString());

        } catch (OAuthMessageSignerException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (OAuthNotAuthorizedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (OAuthExpectationFailedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (OAuthCommunicationException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(authUrl)));
    }

    @Override
    protected void onResume() {
        // this must be places in activity#onResume()  
        Uri uri = this.getIntent().getData();  
        if (uri != null && uri.toString().startsWith(CALLBACK_URL)) {  
            String verifier = uri.getQueryParameter("oauth_verifier");  
            // this will populate token and token_secret in consumer  
            try {
                provider.retrieveAccessToken(consumer, verifier);
            } catch (OAuthMessageSignerException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (OAuthNotAuthorizedException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (OAuthExpectationFailedException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (OAuthCommunicationException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }  
        }  
        super.onResume();
    }
}

我的 AndroidManifest.xml 看起来像这样

<uses-permission
    android:name="android.permission.INTERNET"/>
<application
    android:icon="@drawable/icon"
    android:label="@string/app_name"
>
    <activity
        android:name=".Tweeter"
        android:label="@string/app_name"
    >
        <intent-filter>
            <action
                android:name="android.intent.action.MAIN"/>
            <category
                android:name="android.intent.category.LAUNCHER"/>
        </intent-filter>
    </activity>
    <intent-filter>
        <action
            android:name="android.intent.action.VIEW"
        ></action>
        <category
            android:name="android.intent.category.DEFAULT"
        ></category>
        <category
            android:name="android.intent.category.BROWSABLE"
        ></category>
        <data
            android:scheme="PicPuzzle"
            android:host="tkxel"
        ></data>
    </intent-filter>
</application>
<uses-sdk
    android:minSdkVersion="7"/>`enter code here`

1 个答案:

答案 0 :(得分:7)

回调网址应基于您在清单中为活动配置的内容。您似乎正在使用scheme="PicPuzzle"host="tkxel"。因此,您的回调网址为PicPuzzle://tkxel

我认为<data>标记应该在您希望接收回调的特定Activity上(看起来您现在已经在整个应用程序中拥有它)。