Question

我们有一个对象数组

var myArr = [ {name: "john", age:23, conflict:['booking', ' double booking']}
              {name: "john", age:43, conflict:['booking', ' double booking']}
              {name: "jim", age:101, conflict:['normal', ' double booking']}
              {name: "bob", age:67, conflict:['cancelled', ' double booking']} ];

如何从myArr获取对象列表，其中的冲突对象在其中具有正常值？

Answer 1

您可以使用filter和find来获取冲突数组中normal的对象。

＆＃13;

var myArr = [ {name: "john", age:23, conflict:['booking', ' double booking']},{name: "john", age:43, conflict:['booking', ' double booking']},{name: "jim", age:101, conflict:['normal', ' double booking']},{name: "bob", age:67, conflict:['cancelled', ' double booking']} ],
    searchWord = 'normal';

var result = _.filter(myArr, function(o) { 
  return _.find(o.conflict, function(word) { 
    return word.toLowerCase() == searchWord.toLowerCase(); 
  }); 
});
console.log(result);

＆＃13;

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>

＆＃13;

Loadash：从数组对象中过滤

1 个答案: