Question

说我有一个名为entity的{{1}}，如下所示

UserSchedule

在我的@Entity @Table(name = "user_schedule") public class UserSchedule { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private long id; @Column(name = "user_id") private long userId; @OneToMany(cascade = CascadeType.ALL) @JoinColumn(name = "schedule_id", referencedColumnName = "id") private Set<Schedule> schedules; }中，我想过滤日程安排。这样的事情UserScheduleRepository。但由于时间表是一个集合而不是@Query("select us from UserSchedule us where us.schedules.id = 1")实体，因此这不合法。如何在休眠中实现这一点？

Answer 1

您可以使用JPQL联接（JPQL Joins Documentation）

@Query("select us from UserSchedule us, IN(us.schedules) sh where sh.id  = ?1")
UserSchedule getByScheduleId1(long id);

@Query("select us from UserSchedule us join us.schedules sh where sh.id  = ?1")
UserSchedule getByScheduleId2(long id);

如果您有@ManyToOne反向引用字段，请

@Entity
@Table(name = "schedule")
public class Schedule {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private long id;

    @ManyToOne
    private UserSchedule schedule;

...

您也可以尝试类似

的内容

@Query("select us from UserSchedule us where us.id in (select s.schedule from Schedule s where s.id = ?1 )")

如何使用@Query在hibernate中对集合的where子句做什么？

1 个答案: