所以我写了这段代码,然后我写了#34; int number = input.nextInt(); "在它作为一个实验。该计划正是我想要的,但我不明白为什么这样做。稍后在程序中根本不使用该变量,但如果我将其删除,程序将停止工作。有任何想法吗?我的代码如下:
import java.util.Scanner;
/*
* Name: Ki
*/
public class Countdown {
public static void main(String[] args) {
//Create a Scanner object to accept the input from user
Scanner input = new Scanner(System.in);
// Prompt the user to enter starting number, I just set it to 5 because
// that's what the program had as standard input.
System.out.println("Enter the beginning number: ");
// I don't know how this works. I had this here as an experiment, but
// the program now doesn't work without it so I guess I'll leave it here.
int number = input.nextInt();
// sets max countdown value
int i=5;
// Make a loop that makes the program countdown until it reaches 2
while(i>1)
{
System.out.print(i + " ... \n");
i--;
}
// Makes the program print 1 without dots and print stopped at the end
if (i==1) System.out.println(i);
System.out.print("Stopped");
}
}
答案 0 :(得分:1)
int number = input.nextInt();
// sets max countdown value
// Make a loop that makes the program countdown until it reaches 2
while(number>1)
{
System.out.print(number + " ... \n");
number--;
}
// Makes the program print 1 without dots and print stopped at the end
if (number==1) System.out.println(number);
System.out.print("Stopped");
答案 1 :(得分:0)
在这里创建扫描仪,但它对用户没有任何作用。
Scanner input = new Scanner(System.in);
使用nextInt()
,程序将等待用户输入。
int number = input.nextInt();
但之后你总是使用i
,设置为5。
我想您想使用输入数字作为起始编号。将后半部分更改为:
// You can remove: int i=5;
while(number>1)
{
System.out.print(number + " ... \n");
number--;
}
// Makes the program print 1 without dots and print stopped at the end
if (number==1) System.out.println(number);
System.out.print("Stopped");