ES5语法：

Question

我有这个字符串：

var case1 = '5.25 - 12.25, 13 - 18.5';
var case2 = '6.5 - 12, 13 - 18.5';
var case3 = '9 - 13, 14 - 18';

我需要将它们转换为：

result1; //05:15 - 12:15, 13:00 - 18:30;
result2; //06:30 - 12:00, 13:00 - 18:30;
result3; //09:00 - 13:00, 14:00 - 18:00;

是否可以只使用正则表达式？

规则：

1）如果数字小于10，则添加前导0 2）将.25替换为:15，将.5替换为:30
3）如果该点之后没有任何内容，请添加00

我尝试用条件，替换等来做它，但它很乱。

Answer 1

您可以使用一个正则表达式，但使用replace回调函数：

＆＃13;

const cases = [
    '5.25 - 12.25, 13 - 18.5',
    '6.5 - 12, 13 - 18.5',
    '9 - 13, 14 - 18'
];

const result = cases.map( c => c.replace(/(\d+)(\.\d+)?/g, (_, h, m) => 
    ('0'+h).substr(-2) + ':' + ('0' + (Math.floor(m*60) || 0)).substr(-2)
));

console.log(result);

＆＃13;

ES5语法：

＆＃13;

var cases = [
    '5.25 - 12.25, 13 - 18.5',
    '6.5 - 12, 13 - 18.5',
    '9 - 13, 14 - 18'
];

var result = cases.map(function (c) {
    return c.replace(/(\d+)(\.\d+)?/g, function (_, h, m) { 
        return ('0'+h).substr(-2) + ':' + ('0' + (Math.floor(m*60) || 0)).substr(-2);
    });
});

console.log(result);

＆＃13;

Answer 2

非正则表达式解决方案：

const cases = [
  '5.25 - 12.25, 13 - 18.5',
  '6.5 - 12, 13 - 18.5',
  '9 - 13, 14 - 18'
];

const result = cases.map( c =>
   c.split(", ").map(range =>
      range.split(" - ").map(time => {
         const [hours,mins] = time.split(".");
         return ("00"+hours).substr(-2)+":"+(Math.floor( mins*6/10 ) || "00");
      }).join(" - ")
   ).join(", ")
);

In action

Answer 3

＆＃13;

var cases = ['5.25 - 12.25, 13 - 18.5',
'6.5 - 12, 13 - 18.5',
'9 - 13, 14 - 18'];

cases.forEach(function(src){
  var times = src.replace(/([\d\.])+/g,function(match){
    var seconds = match*60;
    var minutes = parseInt(seconds/60);
    var seconds = "00" + seconds%60;
    seconds = seconds.substr(seconds.length-2);
    return minutes+":"+seconds;

  });  
  console.log(times);
});

＆＃13;

将值转换为可读小时数

3 个答案:

ES5语法：