Question

我正在开发一个使用Json API数据的Android应用程序。 Json API返回一个对象数组，如下所示：

[
  {
    "idProduct": 1,
    "price": 25.9,
    "tpPrice": v1
  },
  {
    "idProduct": 1,
    "price": 29.9,
    "tpPrice": v2
  },
  {
    "idProduct": 2,
    "price": 19.9,
    "tpPrice": v1
  },
  {...}
]

如您所见，API返回两个具有相同ID但价格不同的对象。

我想实现一个解决方案，我可以将这个json修改为：

[
  {
    "idProduct": 1,
    "prices": [
      {
        "price": "25.9,
        "tpPrice": v1
      },
      {
        "price": "29.9,
        "tpPrice": v2
      }
    ]
  },
  {
    "idProduct": 2,
    "prices" [
      {
        "price": "19.9,
        "tpPrice": v1
      }
    ]
  },
  {...}
]

如果有必要的话，那就是我的WebServiceManager，我正在使用Gson。

public class WebServiceManager extends AsyncTask<String, String, List<Object>> {

   private IWebServiceManager iWebServiceMngr;

   private Context ctx;
   private ProgressDialog progress;
   private String messageError = null;
   private String bean = null;
   //private final String URL = "http://192.168.7.1:8080/WSPrePedidos/api/consulta/";
   private final String URL_BASE = "/WSPrePedidos/api/consulta/";
   private final String PATH = "br.com.example.model.";

   @Override
   protected void onPreExecute() {
       super.onPreExecute();

       progress = new ProgressDialog(ctx);
       progress.setCancelable(false);
       progress.setMessage(ctx.getString(R.string.progress_start));
       progress.show();
   }

   /**
    * 0 - Access
    * 1 - Parameters
    * 2 - Class
    *
    * @param params
    * @return
    */
   @Override
   protected List<Object> doInBackground(String... params) {

       bean = params[2].toString();
       publishProgress(ctx.getString(R.string.progress_middle));

       HttpURLConnection urlConnection = null;
       BufferedReader reader = null;
       List<Object> lstObj = new ArrayList<>();
       try {
           URL url = new URL(params[0] + URL_BASE + params[1]);
           Log.i("URL: ", url.toString());
           urlConnection = (HttpURLConnection) url.openConnection();
           urlConnection.setRequestMethod("GET");
           urlConnection.setConnectTimeout(50000);
           urlConnection.setReadTimeout(50000);
           urlConnection.connect();

           int cdResposta = urlConnection.getResponseCode();

           InputStream inputStream;
           if (cdResposta < HttpURLConnection.HTTP_BAD_REQUEST) {
               Log.i("InputStream Ok: ", "" + cdResposta);
               inputStream = urlConnection.getInputStream();
           } else {
               Log.i("InputStream ferrado: ", "" + cdResposta);
               inputStream = urlConnection.getErrorStream();
               messageError = ctx.getString(R.string.message_fail_generic);
           }

           reader = new BufferedReader(new InputStreamReader(inputStream));

           JsonElement je = new JsonParser().parse(reader);
           Gson gson = new Gson();
           if (!je.isJsonObject()) {
               for (JsonElement element : je.getAsJsonArray()) {
                   lstObj.add(gson.fromJson(element.getAsJsonObject(), Class.forName(PATH + bean)));
               }
           } else if (je.isJsonObject()) {
               messageError = null;
               JsonObject jsonObject = je.getAsJsonObject();
               if (jsonObject.get("error") == null) {
                   lstObj.add(gson.fromJson(je.getAsJsonObject(), Class.forName(PATH + bean)));
               }
           }


       } catch (Exception e) {
           e.printStackTrace();
           messageError = ctx.getString(R.string.message_fail_connect_server);
       } finally {
           try {
               if (urlConnection != null)
                   urlConnection.disconnect();
               if (reader != null)
                   reader.close();
           } catch (IOException e1) {
               //e1.printStackTrace();
           }
       }

       return lstObj;
   }

   @Override
   protected void onProgressUpdate(String... params) {
       progress.setMessage(params[0]);
   }

   @Override
   protected void onPostExecute(List<Object> lstObj) {
       super.onPostExecute(lstObj);

       iWebServiceMngr.posExecuteAsyncTaskResult(lstObj, bean, messageError);
       progress.dismiss();
   }

   public WebServiceManager(Context ctx, IWebServiceManager iWebServiceMngr) {
       this.ctx = ctx;
       this.iWebServiceMngr = iWebServiceMngr;
   }
}

抱歉我的英文不好。
我试图尽可能具体。

Answer 1

创建＆＃34;产品＆＃34;包含价格图的对象。在您的JSON响应上迭代它并使用逻辑：

如果产品不存在，请创建产品并应用价格。如果它确实存在且价格ID也存在，则覆盖价格。如果确实存在并且价格ID不存在，请将价格添加到地图中。

如何在java（Android App）中修改Json结构？

1 个答案: