Question

我正在尝试处理具有非连续数字的数组。这是我的示例var myArray = [2, 4, 6, 8]。缺席的数字是3, 5, 7 and the quantity = 3。我试着用这个函数`

来搞定它

＆＃13;

function makeArrayConsecutive(myArray) {
    return Math.max(myArray) - Math.min(myArray) + 1 -  myArray.length;
}
var myArray = [2, 4, 6, 8];
console.log(makeArrayConsecutive(myArray));

＆＃13;

这必须返回3 ...但是它返回NaN ...问题是什么？

Answer 1

以下是我认为适合您的一个解决方案：

function makeArrayConsecutive(arr) {
  //get the min and max using reduce
  var max = arr.reduce(function(a, b) {
    return Math.max(a, b);
  });

  var min = arr.reduce(function(a, b) {
    return Math.min(a, b);
  });

  //amount of numbers b/t min/max if array had no "gaps"
  var deltaDesired = ((max - min) - 1);
  //actual amount of numbers b/t min/max in our array
  var deltaActual = (arr.length - 2);

  return (deltaDesired - deltaActual);
}

var myArray = [2, 4, 6, 8];
console.log(makeArrayConsecutive(myArray));

试图在数组中获取大量缺少的元素

1 个答案: