Question

我正在制作程序，它提取给定字符串的某些部分。但它在函数extct()中的for循环中有一些问题; for循环不会由a<=b终止。它只是通过它并终止于a!='\0'。

int main()
{
    void extct();
    char my_string[50];

    printf("Enter anything: ");
    scanf("%[^\n]s",my_string);

    extct(my_string);

    getch();
    return 0;
}

void extct(char *a)
{
    int i,j,l;
    char new_string[50];

    printf("Enter location from you want to extract string: ");
    scanf("%d",&i);
    printf("Now enter no. of letters you want to extract from previous entered location: ");
    scanf("%d",&j);

    a=a+(i-1);    //sets address to entered location

    int b=a+j;  //sets limit for the for loop

    for(l=0;(a<=b)||(*a!='\0');a++,l++)
    {
        new_string[l]=*a;
    }
    new_string[l]='\0';
    printf("\n%s",new_string);

}

Answer 1

如果您想在任何条件满足时终止循环，则使用&&代替||

  for(l=0;(a<=b) && (*a!='\0');a++,l++)

for循环不会在C中终止

1 个答案: