Question

我在CodeIgniter中创建了一个网站，我想知道如何使用user_id行回显一些用户数据并在个人资料视图页面上回显它？

这是我的身份验证控制器（登录和注册）

<?php

public function login() {
//laad login view

    $this->form_validation->set_rules('email', 'Email', 'required');
    $this->form_validation->set_rules('wachtwoord', 'Wachtwoord', 'required|min_length[5]');
    if ($this->form_validation->run() == TRUE) {

        $email = $_POST['email'];
        $wachtwoord = ($_POST['wachtwoord']);


//check gebruiker in database
        $this->db->select('*');
        $this->db->from('users');
        $this->db->where(array('email' => $email, 'wachtwoord' => $wachtwoord));
        $query = $this->db->get();

        $user = $query->row();
//Als gebruiker bestaat
        if ($user->email) {

//tijdelijke berichten wanneer ingelogd of inloggen niet gelukt
            $this->session->set_flashdata("success", "U bent nu ingelogd");

            $_SESSION['user_logged'] = TRUE;
            $_SESSION['user_id'] = $user->user_id;
            $_SESSION['email'] = $user->email;
            $_SESSION['voornaam'] = $user->voornaam;
            $_SESSION['achternaam'] = $user->achternaam;
            $_SESSION['woonplaats'] = $user->woonplaats;
            $_SESSION['straat'] = $user->straat;
            $_SESSION['huisnummer'] = $user->huisnummer;
            $_SESSION['postcode'] = $user->postcode;
            $_SESSION['beschrijving'] = $user->beschrijving;
            $_SESSION['profiel_foto'] = $user->profiel_foto;


//link naar profiel pagina
            redirect("user/profile", "refresh");
        } else {

            $this->session->set_flashdata('error', 'Invalid email or password');
//wanneer er een foutmelding is link weer naar de login pagina
            redirect("https://kadokado-ferran10.c9users.io/auth/login", "refresh");
        }
    }
//laad login view
    $this->load->view('login');
}



public function register() {

    if (isset($_POST['register'])) {
        $this->form_validation->set_rules('email', 'Email', 'required');
        $this->form_validation->set_rules('voornaam', 'Voornaam', 'required');
        $this->form_validation->set_rules('wachtwoord', 'Wachtwoord', 'required|min_length[5]');
        $this->form_validation->set_rules('wachtwoord', 'Herhaal wachtwoord', 'required|min_length[5]|matches[wachtwoord]');
        $this->form_validation->set_rules('achternaam', 'Achternaam', 'required');
        $this->form_validation->set_rules('postcode', 'Postcode', 'required');
        $this->form_validation->set_rules('woonplaats', 'Woonplaats', 'required|min_length[3]');
        $this->form_validation->set_rules('beschrijving', 'Beschrijving', 'required|min_length[5]');
        $this->form_validation->set_rules('huisnummer', 'Huisnummer', 'required');
        $this->form_validation->set_rules('geboortedatum', 'Geboortedatum', 'required');
        $this->form_validation->set_rules('geslacht', 'Geslacht', 'required');
//If form validation true
        if ($this->form_validation->run() == TRUE) {
// echo 'form validated';


            $target_dir = "upload/";
            $target_file = $target_dir . time() . basename($_FILES["profiel_foto"]["name"]);
            $imageFileType = pathinfo($target_file, PATHINFO_EXTENSION);
            $imgName = time() . basename($_FILES["profiel_foto"]["name"]);
            move_uploaded_file($_FILES["profiel_foto"]["tmp_name"], $target_file);


//voeg gebruiker toe aan database
            $data = array(
                'voornaam' => $_POST['voornaam'],
                'achternaam' => $_POST['achternaam'],
                'email' => $_POST['email'],
                'wachtwoord' => ($_POST['wachtwoord']),
                'startdatum' => date('Y-m-d'),
                'postcode' => $_POST['postcode'],
                'huisnummer' => $_POST['huisnummer'],
                'woonplaats' => $_POST['woonplaats'],
                'beschrijving' => $_POST['beschrijving'],
                'geboortedatum' => $_POST['geboortedatum'],
                'geslacht' => $_POST['geslacht'],
                'profiel_foto' => $imgName
            );
            $this->db->insert('users', $data);

            $this->session->set_flashdata("success", "Uw account is nu geregistreerd, u kunt nu inloggen");
            redirect("auth/register", "refresh");
        }
    }
//Laad de registreer view
    $this->load->view('register');
}
?>

因此，我想在配置文件视图页面上回显2行电子邮件和voornaam。我怎么能这样做？

Answer 1

您只需将数据传递到控制器中，然后就可以使用视图中的所有数据来回显您想要的任何内容，$ data应该是数组或对象：

$this->load->view('register',$data);

在视图中，您可以访问它。

<?php $voornaam ?>
<?php $email ?>

有关详细信息，请阅读官方文档： https://www.codeigniter.com/user_guide/general/views.html

Answer 2

$this->load->view('register',$data);

将所有值作为数组放入控制器中。

在视图文件中。你可以像bellow一样使用

<?=$voornaam ?>
<?=achternaam ?>

Answer 3

您可以在模型中粘贴代码

function get_user_by_id($id = null)
{
   if($id!= null)
   {
       $condition = array('id' => $id);
       $result = $this->main_model->get($condition, 'table-name');
           foreach($result as $row)
           {
               return $row->fname.' '.$row->lname;
           }
   }
    else
    {


    $data =  $this->session->userdata('session-name');
    $result =  $this->main_model->get(array('id' => $data['id']), 'table-name');
    foreach($result as $row)
    {
        return $row->fname.' '.$row->lname;
    }
    }
}

也可以像下面那样打电话

echo $this->model_name->get_user_by_id(5);

如果您传递用户ID，则返回用户名，否则返回会话用户名您应该根据需要更改数据库字段名称

使用user_id codeigniter

3 个答案: