Question

我尝试做字典循环。例如

A = {"Name":1,"Price":2}
B = {"Name":3,"Price":6}
C = {"Name":"","Price":3}

我想要一起添加A B和C

C = {"Name":[1,3,],"Price":[2,6,3]}

我该怎么做？谢谢这是我尝试从住宿页面获取数据的实际代码。它仍然缺少我将所有数据字典放在一起并循环到下一页的部分，并且顺便感谢你。

            from bs4 import BeautifulSoup as soup 
            import re
            from selenium import webdriver
            driver = webdriver.Firefox()
            my_url = 'https://www.hipflat.co.th/en/search/sale/condo_y/any_r1/any_r2/any_p/any_b/any_a/any_w/any_o/any_i/100.62442610451406,13.77183154691727_c/12_z/list_v'
            driver.get(my_url)
            html = driver.page_source
            page_soup = soup(html)
            #Grab Condo
            Condo = page_soup.findAll("li",{"class":"listing"})
            for Con in Condo:
                Name = Con.findAll("div",{"class":"listing-project"})[0].text.strip()
                Description = Con.p.text
                Price = Con.findAll("div",{"class":"listing-price"})[0].text.strip()
                Type = Con.findAll("ul",{"class":"listing-detail"})[0].text.replace("\n","")
                Type = [Name]+[Price]+[Description]+re.split(r'(bed|bath|m2)',Type) 
                Data = {"Name" : Name,"Description" : Description,"Price":Price,"Bed":Type[3],"Bath":Type[5],"Area(m2)":Type[7],"Floor":Type[9]}
                print(Data)
            next_page = driver.find_element_by_xpath('//*[@id="page-content"]/div[2]/div/div[2]/div[1]/div[2]/div/div[3]/a[1]').click()

Answer 1

你可以循环键（其中一个键）。

indicts = [{}, {}...]
outdict = {}
for k in indicts[0].keys():
    outdict[k] = [d[k] for d in indicts]

Answer 2

组合这样的词组的基本方法是检查键是否在结果字典中，如果是，则将值添加到列表中，否则如果键不存在，则添加新列表有价值。

result = {}

for dicti in (A, B, C):
    for key, value in dicti.items():
        if key in result:
            result[key].append(value)
        else:
            result[key] = [value]

这样做的现代方法是使用collections.defaultdict list作为default_factory函数传递。它与上面基本相同，如果缺少密钥，则插入一个带有值的新列表。

from collections import defaultdict

result = defaultdict(list)

for dicti in (A, B, C):
    for key, value in dicti.items():
        result[key].append(value)

一起添加Dictionary值组

2 个答案: