Question

我在我的活动中使用Asynctask，我想使用asynctask获取url的html内容...我在一段时间内成功地修改了html内容但有时候没有发生任何事情......我无法获得html及其内容给我黑屏并给出ANR的错误...

我的活动编码......

public class ControlActivity extends AppCompatActivity {

    private static TextView txt1, txt2, txt3, txt4,txt5,txt6,txt7,txt8;
    private static SwitchCompat switch1, switch2, switch3, switch4, switch5, switch6, switch7, switch8;
  //  private static ImageView image1,image2,image3,image4,image5,image6,image7,image8;
    private static Button allon,alloff;
    String t1,t2,t3,t4,t5,t6,t7,t8;


    SwipeRefreshLayout swipe_container;

    JSONArray data = null;

    Handler mHandler;
    private static String ip,port,uname,password;
    private static Document htmlDocument;
    private static String htmlContentInStringFormat,content;
    private static String stringuri;
    private static List<String> listOfString = new ArrayList<String>();

    @Override
    protected void onCreate(Bundle savedInstanceState) {

        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_control);
        new JSONAsyncTask().execute();
class JSONAsyncTask extends AsyncTask<String, Void, Boolean> {
        @Override
        protected void onPreExecute() {
            super.onPreExecute();

        }

        @Override
        protected Boolean doInBackground(String... urls) {
            StringBuffer stringBuffer = new StringBuffer("");
            BufferedReader bufferedReader = null;
            try {
                HttpClient httpClient = new DefaultHttpClient();
                HttpGet httpGet = new HttpGet();

                URI uri = new URI("http://"+ip+":"+port+"/index.htm");

                httpGet.setURI(uri);
                httpGet.addHeader(BasicScheme.authenticate(
                        new UsernamePasswordCredentials(uname, password),
                        HTTP.UTF_8, false));

                HttpResponse httpResponse = httpClient.execute(httpGet);

                // Read the contents of an entity and return it as a String.
                content = EntityUtils.toString(httpResponse.getEntity());

                Log.e("content: ", "> " + content);





              //  listOfString.clear();



                InputStream inputStream = httpResponse.getEntity().getContent();
                bufferedReader = new BufferedReader(new InputStreamReader(
                        inputStream));

                String readLine = bufferedReader.readLine();
                while (readLine != null) {
                    stringBuffer.append(readLine);
                    stringBuffer.append("\n");
                    readLine = bufferedReader.readLine();
                }

            }  catch (Exception e) {
                // TODO: handle exception
            } finally {
                if (bufferedReader != null) {
                    try {
                        bufferedReader.close();
                    } catch (IOException e) {
                        // TODO: handle exception
                    }
                }
            }
            return false;
        }

        protected void onPostExecute(Boolean result) {

            txt1=(TextView)findViewById(R.id.txt1);
            txt2=(TextView)findViewById(R.id.txt2);
            txt3=(TextView)findViewById(R.id.txt3);
            txt4=(TextView)findViewById(R.id.txt4);
            txt5=(TextView)findViewById(R.id.txt5);
            txt6=(TextView)findViewById(R.id.txt6);
            txt7=(TextView)findViewById(R.id.txt7);
            txt8=(TextView)findViewById(R.id.txt8);

            Document doc = Jsoup.parse(content);
            htmlContentInStringFormat = doc.title();

            Elements td=doc.getElementsByTag("td");
            //Log.e("td: ", "> " + td);

            String td1=td.toString();
            //  Log.e("td1: ", "> " + td1);

            Elements articles = doc.select("td");

            for (Element element : articles) {
                String content1 = element.text();
                Log.e("content1: ", "> " + content1);
                listOfString.add(content1);
                System.out.println(content1);
            }

            t1 = listOfString.get(26);
            t2 = listOfString.get(31);
            t3 = listOfString.get(36);
            t4 = listOfString.get(41);
            t5 = listOfString.get(46);
            t6 = listOfString.get(51);
            t7 = listOfString.get(56);
            t8 = listOfString.get(61);

            Log.e("t1: ", "> " + t1);
            Log.e("t2: ", "> " + t2);
            Log.e("t3: ", "> " + t3);
            Log.e("t4: ", "> " + t4);
            txt1.setText(t1);
            txt2.setText(t2);
            txt3.setText(t3);
            txt4.setText(t4);
            txt5.setText(t5);
            txt6.setText(t6);
            txt7.setText(t7);
            txt8.setText(t8);

        }
    }
}

它给我这样的roor ..

Answer 1

应用程序无响应（ANR） - 如果我们在主（UI）线程中执行任何繁重的功能以及UI修改，将会发生。如果在UI线程中发生耗时的繁重计算，则会延迟对用户操作的响应，这可能会刺激用户，从而停止进程。事实上，2.3.3以上的Android版本（Gingerbread）严格禁止在UI线程中进行大量处理，并允许用户使用ANR对话框关闭应用程序。

解决方案 - 仅在主线程中运行UI组件，并将其他计算移至后台线程。在这种情况下，将解析工作移到后台线程，并将解析后的结果传递给onPostExecute（）调用。

注意 - 在您的应用执行可能冗长的操作的任何情况下，您都不应该在UI线程上执行工作，而是创建工作线程并在那里完成大部分工作。

如何解决某些应用程序活动中的ANR错误？

1 个答案: