嗨,我是php的初学者,谁能告诉我这里的问题是什么?我似乎无法解决它。这是我的PHP编码:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "tempahperalatan";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
if(isset($_POST['submit']))
{
$pemohon = $_POST['namaPemohon'];
$trkhMula = $_POST['tmula'];
$trkhAkhir = $_POST['takhir'];
$n_program = $_POST['namaProgram'];
$lokasi = $_POST['lokasi'];
$n_anjuran = $_POST['namaAnjuran'];
$catatan = $_POST['catatan'];
$sql = "INSERT INTO daftartempah (pemohon, trkhMula, trkhAkhir, n_program, lokasi, n_anjuran, catatan) VALUES ('$namaPemohon', '$tmula', '$takhir', '$namaprogram', '$lokasi', '$namaAnjuran', '$catatan')";
}
if (mysqli_query($conn, $sql)) { //this is line 30
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
mysqli_close($conn);
?>
它与我的xampp有什么关系吗?提前谢谢你:)
答案 0 :(得分:3)
放置代码块
$bundles = array(
new Symfony\Bundle\FrameworkBundle\FrameworkBundle(),
new Symfony\Bundle\SecurityBundle\SecurityBundle(),
new Symfony\Bundle\TwigBundle\TwigBundle(),
new Symfony\Bundle\MonologBundle\MonologBundle(),
new Symfony\Bundle\SwiftmailerBundle\SwiftmailerBundle(),
new Doctrine\Bundle\DoctrineBundle\DoctrineBundle(),
new Sensio\Bundle\FrameworkExtraBundle\SensioFrameworkExtraBundle(),
new AppBundle\AppBundle(),
new FOS\UserBundle\FOSUserBundle(),
);
里面的
if (mysqli_query($conn, $sql)) { //this is line 30
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
正好在$ sql = [...]
之下否则如果您的表单未提交,脚本将尝试执行不存在的查询
答案 1 :(得分:0)
低于$ sql,取一个变量
<class 'novaclient.base.ListWithMeta'>