从双向链表中删除光标

时间:2017-09-26 03:04:08

标签: java linked-list computer-science doubly-linked-list

我试图从列表中删除光标并使其引用前一个CarListNode(或者如果光标先前引用了列表的头部,则为头部)。同时仍然返回光标内的信息。 我的代码没有正确删除光标。我的代码中有什么问题?

这是我目前的代码:

public Fruit removeCursor() throws EndOfListException {

    if (cursor == null) {
        throw new EndOfListException();

    } else if (cursor.getPrev() == null) {
        head = cursor.getNext();
        cursor.setNext(null);
        cursor.setPrev(null);
        cursor = head;

    } else if (cursor.getNext() == null) {
        tail = cursor.getPrev();
        cursor.setPrev(null);
        cursor.setNext(null);
        cursor = tail;

    } else {
        cursor.setData(cursor.getNext().getData()); //this isn't a singly linked list
        cursor.setNext(cursor.getNext().getNext());
    }

    count--;

    return cursor.getData();
}

1 个答案:

答案 0 :(得分:0)

您的else子句没有"删除光标" ...

尝试这样的事情:

else {
    cursor.getPrev().setNext(cursor.getNext());
    cursor.getNext().setPrev(cursor.getPrev());
    // You might want to release the cursor's item, EG:
    cursor = null;
    cursor = cursor.getNext();
}