我有一个代码,我需要帮助。基本上,我有一个有4张幻灯片的面板。我使用代码$(" .two")隐藏第二张幻灯片.delech();.我试图实现的目标是:当我选中幻灯片1中的复选框时,第二张幻灯片应该在选择"下一步" (基本上没有跳过第二张幻灯片)。否则第二张幻灯片会跳过。如何在幻灯片1中选中复选框时如何显示幻灯片2?
我尝试使用append()以第二张幻灯片定位复选框,但2幻灯片面板仍然隐藏。 (如果我大吼大叫,请解释为什么我将来可以在论坛上进行改进。)谢谢你的时间!
$(document).ready(function() {
var $fieldsets =
$('#panels .sets')
.first()
.addClass('active')
.end()
.not(':first')
.hide()
.end();
$(':nth-child(3)').removeClass("active").css('display', 'none');
var $panelControlButtons =
$('#panelcontrol button')
.filter('.btnPrev')
.prop('disabled', true)
.end();
$('#panelcontrol')
.on('click', 'button', function(e) {
e.preventDefault();
switch (true) {
case $(this).hasClass('btnNext'):
var $newFieldset =
$fieldsets
.filter('.active')
.hide()
.removeClass('active')
.next()
.addClass('active')
.show();
//enable Prev button
$panelControlButtons
.filter('.btnPrev')
.prop('disabled', false);
//disabled Next button
if ($newFieldset.is(':last-child')) {
$panelControlButtons
.filter('.btnNext')
.prop('disabled', true);
}
break; // btnNext
var $input =
$('input')
.filter('.active')
.end();
case $(this).hasClass('btnPrev'):
var $newFieldset =
$fieldsets
.filter('.active') //selects the current fieldset
.hide() //hide it
.removeClass('active') //remove active flag
.prev() //move to the previous fieldset
.addClass('active') //flag as active
.show(); //and show it
// enable Next button
$panelControlButtons
.filter('.btnNext')
.prop('disabled', false);
// disable Prev button
if ($newFieldset.is(':first-child')) {
$panelControlButtons
.filter('.btnPrev')
.prop('disabled', true);
}
break; // btn Prev
}
}); // panelcontrol button handler
/*skips panel two*/
$(".two").detach();
});

<!doctype html>
<html lang="engl">
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.0/jquery.min.js"></script>
<link href="https://fonts.googleapis.com/css?family=Lato:700" rel="stylesheet">
<link rel="stylesheet" href="style.css">
<link rel="stylesheet" href="simplegrid.css">
<script src="jquery/main.js"></script>
<meta charset="utf-8">
<title>Stylus Simulator</title>
</head>
<body>
<div id="container">
<div id="panels">
<div class="sets">
<h1>PANEL 1</h1>
<form action="">
<input type="checkbox" name="vehicle" value="Bike">I have a bike<br>
<input type="checkbox" name="vehicle" value="Car">I have a car
</form>
<div><input type="text" name="ss1" value="" /></div>
</div>
<div class="sets two">
<h1>PANEL 2</h1>
<div><input name="ss2" value="" /></div>
</div>
<div class="sets">
<h1>PANEL 3</h1>
</div>
<div class="sets">
<h1>PANEL 4</h1>
</div>
</div>
</div>
<div id="panelcontrol">
<button class="btnPrev">Prev</button>
<button class="btnNext">Next</button>
</div>
<script type="text/javascript" src="jquery-3.2.1.js"></script>
</body>
</html>
&#13;
答案 0 :(得分:0)
您可以使用解决方案
$(document).ready(function() {
var skipPanel2 = true;
function enableDisablePrevNex(){
if($('.active').index() === 0){
$('.btnPrev').prop('disabled', 'disabled');
$('.btnNext').removeAttr('disabled');
if($('input[name="vehicle"]').is(':checked')){
skipPanel2 = false;
} else {
skipPanel2 = true;
}
} else if($('.active').index() === 3){
$('.btnNext').prop('disabled', 'disabled');
$('.btnPrev').removeAttr('disabled');
} else {
$('.btnPrev, .btnNext').removeAttr('disabled');
}
}
//Initial Call
enableDisablePrevNex();
$('input[name="vehicle"]').change(function(){
if($(this).is(':checked'))
skipPanel2 = false;
});
$('.btnNext').click(function(){
slideNext();
});
$('.btnPrev').click(function(){
var activeSet = $('.active').index();
$('.sets:nth-child(' + (activeSet + 1) + ')').removeClass('active');
$('.sets:nth-child(' + activeSet + ')').addClass('active');
enableDisablePrevNex();
});
function slideNext(){
var activeSet = $('.active').index();
if(activeSet === 0){
if(skipPanel2){
$('.sets:nth-child(' + (activeSet + 1) + ')').removeClass('active');
$('.sets:nth-child(' + (activeSet + 3) + ')').addClass('active');
} else {
$('.sets:nth-child(' + (activeSet + 1) + ')').removeClass('active');
$('.sets:nth-child(' + (activeSet + 2) + ')').addClass('active');
}
} else {
$('.sets:nth-child(' + (activeSet + 1) + ')').removeClass('active');
$('.sets:nth-child(' + (activeSet + 2) + ')').addClass('active');
}
enableDisablePrevNex();
}
});
.sets {
display: none;
}
.active {
display: block;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="container">
<div id="panels">
<div class="sets active">
<h1>PANEL 1</h1>
<form action="">
<input type="checkbox" name="vehicle" value="Bike">I have a bike<br>
<input type="checkbox" name="vehicle" value="Car">I have a car
</form>
<div><input type="text" name="ss1" value="" /></div>
</div>
<div class="sets">
<h1>PANEL 2</h1>
<div><input name="ss2" value="" /></div>
</div>
<div class="sets">
<h1>PANEL 3</h1>
</div>
<div class="sets">
<h1>PANEL 4</h1>
</div>
</div>
</div>
<div id="panelcontrol">
<button class="btnPrev">Prev</button>
<button class="btnNext">Next</button>
</div>
我无法执行您的代码,因此我尝试使用自己的代码。
希望这会对你有所帮助。