Question

我的碰撞代码确实有问题，因为红色的子弹＆＃39;必须击中玩家的正中间才能在屏幕上运行游戏。我需要帮助重构表达式，所以如果红色的子弹＆＃39;在任何地方点击播放器它将在代码上运行我的游戏（代码游戏接近结束pygame.quit（）之前）

import pygame
import random
BLACK = (0,0,0)
WHITE = (255,255,255)
GREEN = (0,255,0)
RED = (255,0,0)
BLUE = (0,0,255)
pygame.init()
size = (700,700)
screen = pygame.display.set_mode(size)
pygame.display.set_caption("Dodger")
done = False
clock = pygame.time.Clock()

def resetpositions():
    global bulletrect1, bulletrect2, bulletrect3, bulletrect4, bulletrect5, circlerect
    bulletrect1 = pygame.rect.Rect((350, 0, 20, 20))
    bulletrect2 = pygame.rect.Rect((175, 0, 20, 20))
    bulletrect3 = pygame.rect.Rect((525, 0, 20, 20))
    bulletrect4 = pygame.rect.Rect((525, 0, 20, 20))
    bulletrect5 = pygame.rect.Rect((525, 0, 20, 20))

circlerect = pygame.rect.Rect((350, 600, 20, 20))

resetpositions()
while not done:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            done = True
        if event.type == pygame.KEYDOWN:
            circlerect.x += 5
    bulletrect1.y += 1
    bulletrect2.y += 2
    bulletrect3.y += 3
    bulletrect4.y += 4
    bulletrect5.y += 5
    screen.fill(BLACK)
    pygame.draw.circle(screen, GREEN, (circlerect.center), 15)
    pygame.draw.circle(screen, RED, (bulletrect1.center), 20)
    pygame.draw.circle(screen, RED, (bulletrect2.center), 20)
    pygame.draw.circle(screen, RED, (bulletrect3.center), 20)
    pygame.draw.circle(screen, RED, (bulletrect4.center), 20)
    pygame.draw.circle(screen, RED, (bulletrect5.center), 20)
    if bulletrect1.y == 800:
        bulletrect1.y = 0
        bulletrect1.x = random.randint(20,680)
    if bulletrect2.y == 800:
        bulletrect2.y = 0
        bulletrect2.x = random.randint(20,680)
    if bulletrect3.y == 800:
        bulletrect3.y = 0
        bulletrect3.x = random.randint(20,680)
    if bulletrect4.y == 800:
        bulletrect4.y = 0
        bulletrect4.x = random.randint(20,680)
    if bulletrect5.y == 800:
        bulletrect5.y = 0
        bulletrect5.x = random.randint(20,680)
    if circlerect.x == 685:
       circlerect.x = 15
    if circlerect.collidelist((bulletrect1, bulletrect2, bulletrect3, bulletrect4, bulletrect5)) == 0:
        screen.fill(BLACK)
        font = pygame.font.SysFont('Calibri',40,True,False)
        text = font.render("GAME OVER",True,RED)
        screen.blit(text,[250,350])
        pygame.display.update()
        pygame.time.delay(3000)
        resetpositions()
    pygame.display.flip()
    clock.tick(300)
pygame.quit()

Answer 1

pygame.Rect.collidelist返回列表中冲突矩形的索引，这意味着您只检查circlerect是否与索引0处的子弹冲突。如果列表中没有rects，则返回-1，因此如果它没有返回-1，则其中一个rects与玩家发生冲突并且游戏结束：

if circlerect.collidelist((bulletrect1, bulletrect2, bulletrect3, bulletrect4, bulletrect5)) != -1:
    # Game over.

我无法在pygame中获得正确的碰撞代码

1 个答案: