Question

我是SQL的新手所以请原谅我的空白区域。我正在尝试在sqlite中编写一个查询，给我两个值：

列（预算）中具有不同值的所有值的总和从另一列（花费）并将值转换为数千，数百万，数十亿使用k，M和B连接作为后缀
从当前日期（'现在'）减去截止日期（日期）以天为单位获得价值。

这是我使用过的查询，但结果似乎有些偏差而且不准确：

SELECT ( CASE 1 
WHEN SUM(Budget >= 1000 AND Budget < 10000) THEN  '$' || 
substr(Budget,1,1) || '.' || substr(Budget,2,1)  || 'K'
WHEN SUM(Budget  >= 10000 AND Budget < 100000) THEN '$' || 
substr(Budget,1,2) || '.' || substr(Budget,3,1)  || 'K'
WHEN SUM(Budget >= 100000 AND Budget < 1000000) THEN '$' || 
substr(Budget,1,3) || '.' || substr(Budget,4,1)  || 'K'
WHEN SUM(Budget >= 1000000 AND Budget < 10000000) THEN  '$' || 
substr(Budget,1,1) || '.' || substr(Budget,2,1)  || 'M'
WHEN SUM(Budget >= 10000000 AND Budget < 100000000) THEN '$' || 
substr(Budget,1,2) || '.' || substr(Budget,3,1)  || 'M'
WHEN SUM(Budget >= 100000000 AND Budget < 1000000000) THEN '$' || 
substr(Budget,1,3) || '.' || substr(Budget,4,1)  || 'M'
WHEN SUM(Budget >= 1000000000 AND Budget < 10000000000) THEN  '$' || 
substr(Budget,1,1) || '.' || substr(Budget,2,1)  || 'B'
WHEN SUM(Budget >= 10000000000 AND Budget < 100000000000) THEN '$' || 
substr(Budget,1,2) || '.' || substr(Budget,3,1)  || 'B'
WHEN SUM(Budget >= 100000000000 AND Budget < 1000000000000) THEN '$' || 
substr(Budget,1,3) || '.' || substr(Budget,4,1)  || 'B'
ELSE ''
END) AS budget,
(SELECT cast(
     (
              strftime('%d',eventDate)-strftime('%d','now')
     ) AS real
  )) AS days_left, (SELECT (count(spent)) AS total_spent FROM 
`user_selected_items` WHERE `userID` = 'userID' 
AND `Status` IN('0')) AS total_items_left FROM `user_selected_items`

SQLite中的好数字

0 个答案: