Question

我有两个列表，并将这两个列表合并到字典中：

ip = ["1.1.1.1", "2.2.2.2", "3.3.3.3", " 4.4.4.4", "5.5.5.5", "6.6.6.6", "7.7.7.7"]
name = ["ip0", "ip2", "ip2", "ip3", "ip3", "ip3"]

{'ip2': "['2.2.2.2', '3.3.3.3']", 'ip3': "[' 4.4.4.4', '5.5.5.5', '6.6.6.6']", 'ip0': "['1.1.1.1']"}

我想将此词典导出为CSV文件 key在一个单元格中，配对值也应该在下一个单元格中，并且此单元格中应该有多个行用于ip地址。例如：

ip2 2.2.2.2
    3.3.3.3

我应该怎么做？

结合两个列表配置：

k = list(zip(name, ip))
d = {}
for (x,y) in k:
    if x in d:
        d[x] = d[x] +","+ y 
    else:
        d[x] = y

Answer 1

好的，现在我明白了你的意思。以下是更新答案的示例：

print('op:',sess.run(acc_op,{logits:[[0,1,0],[0,1,0]]}))
#op: 0.75 
print('[total, count]:',sess.run(stream_vars)) 
#[total, count]: [3.0, 4.0]

“output.csv”：

ip = ["1.1.1.1", "2.2.2.2", "3.3.3.3", "4.4.4.4", "5.5.5.5", "6.6.6.6", "7.7.7.7"]
name = ["ip0", "ip2", "ip2", "ip3", "ip3", "ip3"]

# Create dictionary
# We use setdefault to list ([]) here to be able to append values to list
# if it does not exist yet.
#d = {}
#for x,y in list(zip(name,ip)):
#    d.setdefault(x, []).append(y)


# But to use your example we can use this small modification:
k = list(zip(name, ip))
d = {}
# Create dictionary
for (x,y) in k:
    if x in d:
        d[x] += [y]
    else:
        d[x] = [y]

# Output dictionary
with open("output.csv", "w") as f:
    for k,v in d.iteritems(): # d.items() if py3
        for ind,item in enumerate(v):
            if ind == 0:
                f.write("{},{}\n".format(k,item))
            else:
                f.write(",{}\n".format(item))

字典现在看起来像这样：

ip0,1.1.1.1
ip2,2.2.2.2
,3.3.3.3
ip3,4.4.4.4
,5.5.5.5
,6.6.6.6

导出python字典，列表作为csv的值

1 个答案: