Question

我需要使用分隔符在列中拆分我的一个列值，下面是表格结构。

create table #a
(
    id int, 
    timeline varchar(100)
)

insert into #a
values (1, 'Semi Annual Q2 (May/June/July) & Q4 (Nov/Dec/Jan)'),
       (2, 'Semi Annual Q1 (Feb/Mar/Apr) & Q3 (Aug/Sep/Oct)'),
       (3, 'Annual Q3 (Aug/Sep/Oct)'),
       (4, 'Annual Q2 (May/June/July)'),
       (5, 'Annual Q4 (Nov/Dec/Jan)'),
       (6, 'Semi Annual Q1 (Jan/Feb/Mar) & Q3 (July/Aug/Sep)')

select * from #a

输出我想用'/'分隔符分割时间轴值，并为单独的月份制作单独的列，所有月份应按顺序排列，看起来像下面的样本。

ID  M1   M2    M3    M4    M5    M6
---------------------------------------
1   May  June  July  Nov   Dec   Jan
2   Feb  Mar   Apr   Aug   Sep   Oct
3   Aug  Sep   Oct   NULL  NULL  NULL
4   May  June  July  NULL  NULL  NULL
5   Nov  Dec   Jan   NULL  NULL  NULL
6   Jan  Feb   Mar   July  Aug   Sep

到目前为止，我已经尝试过这个：

select
    timeline,
    substring((substring(timeline, CHARINDEX('(', timeline) + 1, len(timeline) - 1)), 1, charindex('/', substring(timeline, CHARINDEX('(', timeline) + 1, len(timeline) - 1)) - 1) as M1,
    replace(replace(right(substring(substring(timeline, CHARINDEX('(', timeline) + 1, len(timeline)), 1, charindex(')', substring(timeline, CHARINDEX('(', timeline) + 1, len(timeline)))), charindex('/', reverse(substring(substring(timeline, CHARINDEX('(', timeline) + 1, len(timeline)), 1, charindex(')', substring(timeline, CHARINDEX('(', timeline) + 1, len(timeline))))), 4)), '/', ''), ')', '') as M3
from 
    #a;

这不是代码而且也太乏味了。如果您有有效的方法，请提供帮助。

Answer 1

以下解决方案中使用的SplitCSVToTable8K函数与上面提到的DelimitedSplit8K函数相同...

以下是如何在解决方案中使用它：

RewriteCond %{QUERY_STRING} ^option=com_content&task=view&id=49&Itemid=29$
RewriteRule ^index\.php$ /path/to/new/page? [R=301,L]

结果...

WITH 
    cte_ParseTimeline AS (
        SELECT 
            a.id,
            rn = ROW_NUMBER() OVER (PARTITION BY a.id ORDER BY sc.ItemNumber),
            sc.Item
        FROM 
            #a a
            CROSS APPLY dbo.SplitCSVToTable8K(REPLACE(REPLACE(a.timeline, '(', '/'), ')', '/'), '/') sc
        WHERE 
            sc.Item LIKE ('[A-Z][a-z][a-z]')
            OR 
            sc.Item LIKE ('[A-Z][a-z][a-z][a-z]')
        )
SELECT 
    pt.id,
    M1 = MAX(CASE WHEN pt.rn = 1 THEN pt.Item END),
    M2 = MAX(CASE WHEN pt.rn = 2 THEN pt.Item END),
    M3 = MAX(CASE WHEN pt.rn = 3 THEN pt.Item END),
    M4 = MAX(CASE WHEN pt.rn = 4 THEN pt.Item END),
    M5 = MAX(CASE WHEN pt.rn = 5 THEN pt.Item END),
    M6 = MAX(CASE WHEN pt.rn = 6 THEN pt.Item END)
FROM 
    cte_ParseTimeline pt
GROUP BY
    pt.id;

使用SQL Server通过分隔符在列中拆分字符串

1 个答案: